使用数据集 df:
df
confint row Index
0.3407,0.4104 1 1
0.2849,0.4413 2 2
0.2137,0.2674 3 3
0.1910,0.4575 4 1
0.4039,0.4905 5 2
0.403,0.4822 6 3
0.0301,0.0646 7 1
0.0377,0.0747 8 2
0.0835,0.0918 9 3
0.0437,0.0829 10 1
0.0417,0.0711 11 2
0.0718,0.0798 12 3
0.0112,0.0417 13 1
0.019,0.0237 14 2
0.0213,0.0293 15 3
0.0121,0.0393 16 1
0.0126,0.0246 17 2
0.0318,0.0428 18 3
0.0298,0.0631 19 1
0.018,0.0202 20 2
0.1031,0.1207 21 3
这应该是一个相当容易从长格式转换为宽格式的数据集,即 7(行)x 3(列)数据帧。结果应包含 3 列(由 Index
命名)和 7 行 (21/3 = 7)。代码如下:
df <- spread(df,Index, confint, convert = FALSE)
但是,通过使用 Spread() 我收到以下错误:
Error: Duplicate identifiers for rows (1, 4, 7, 10, 13, 16, 19), (2, 5, 8, 11, 14, 17, 20), (3, 6, 9, 12, 15, 18, 21)
任何帮助将不胜感激!
最佳答案
我们需要创建一个序列列,然后展开
library(tidyverse)
df %>%
group_by(Index) %>%
mutate(ind = row_number()) %>%
spread(Index, confint, convert = FALSE)
注意:这将是原始数据集中的问题,而不是帖子中显示的示例数据的问题
关于R传播错误: Duplicate identifiers for rows,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54068141/