javascript - 如何在reactjs中根据日期降序对对象数组进行排序？

Question

我有一个如下所示的对象数组，并希望按降序对其进行排序。

下面是对象数组

[
{
    "attributes": {

    },
    "timestamp": "2019-04-03T21:00:00+00:00",
},
{
    "attributes": {
    },
    "timestamp": "2019-04-03T09:24:27.179190+00:00",
},
{
    "attributes": {
    },
    "timestamp": "2019-04-03T08:54:06.721557+00:00",
},
{
    "attributes": {

    },
    "timestamp": "2019-04-03T04:54:56.227415+00:00",
},
]

我尝试了什么？

 let sorted_array = this.state.array.sort((a, b) => a.timestamp - 
     b.timestamp);
 this.setState({array: sorted_array});

但这不起作用。 你能帮我解决这个问题吗？

Answer 1

由于时间戳已针对字典排序进行标准化，也许您可​​以使用 String.localeCompare()在 sort 方法上:

let input = [
  {
    "attributes": {},
    "timestamp": "2019-04-03T21:00:00+00:00",
  },
  {
    "attributes": {},
    "timestamp": "2019-04-03T09:24:27.179190+00:00",
  },
  {
    "attributes": {},
    "timestamp": "2019-04-03T08:54:06.721557+00:00",
  },
  {
    "attributes": {},
    "timestamp": "2019-04-03T04:54:56.227415+00:00",
  }
];

input.sort((a, b) => b.timestamp.localeCompare(a.timestamp));
console.log(input);

.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}

如果需要按升序排序，则使用:

input.sort((a, b) => a.timestamp.localeCompare(b.timestamp));