我正在开发一个文件共享应用程序。我需要通过调用 WifiManager.startLocalOnlyHotspot() 以编程方式打开设备的仅限本地热点。
根据此页面上的 android 文档 - https://developer.android.com/reference/android/net/wifi/WifiManager#startLocalOnlyHotspot(android.net.wifi.WifiManager.LocalOnlyHotspotCallback,%2520android.os.Handler) ,
Applications need to have the following permissions to start LocalOnlyHotspot: Manifest.permission.CHANGE_WIFI_STATE and ACCESS_FINE_LOCATION. Callers without the permissions will trigger a SecurityException.
我已在 list 中添加了这两个权限,并在运行时授予了 ACCESS_FINE_LOCATION (因为这是运行时权限(危险权限))。
但在某些设备中调用 startLocalOnlyHotspot() 仍然会抛出 SecurityException。
引发 SecurityException 的设备:Samsung Galaxy J7 Max (j7maxlte)、Android 8.1
运行正常且未抛出异常的设备:Redmi Note 7 Pro、Android 9 PKQ1.181203.001
我错过了什么?
最佳答案
您需要启用 GPS 定位。
首先添加gms的依赖。
implementation 'com.google.android.gms:play-services-location:16.0.0'
之后,设置位置服务
private void setupLocationServices() {
LocationRequest mLocationRequest = new LocationRequest();
mLocationRequest.setInterval(10);
mLocationRequest.setSmallestDisplacement(10);
mLocationRequest.setFastestInterval(10);
mLocationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
LocationSettingsRequest.Builder builder = new
LocationSettingsRequest.Builder();
builder.addLocationRequest(mLocationRequest);
task = LocationServices.getSettingsClient(this).checkLocationSettings(builder.build());
locationSettingsResponseBuilder();
}
LocationSettingsResponseBuilder:
private void locationSettingsResponseBuilder() {
task.addOnCompleteListener(task -> {
try {
LocationSettingsResponse response = task.getResult(ApiException.class);
// All location settings are satisfied. The client can initialize location
// requests here.
//Everything is good. You can turn on hotspot here.
//}
} catch (ApiException exception) {
switch (exception.getStatusCode()) {
case LocationSettingsStatusCodes.RESOLUTION_REQUIRED:
// Location settings are not satisfied. But could be fixed by showing the
// user a dialog.
try {
// Cast to a resolvable exception.
ResolvableApiException resolvable = (ResolvableApiException) exception;
// Show the dialog by calling startResolutionForResult(),
// and check the result in onActivityResult().
resolvable.startResolutionForResult(
MainActivity.this,
101);
} catch (IntentSender.SendIntentException e) {
// Ignore the error.
} catch (ClassCastException e) {
// Ignore, should be an impossible error.
}
break;
case LocationSettingsStatusCodes.SETTINGS_CHANGE_UNAVAILABLE:
// Location settings are not satisfied. However, we have no way to fix the
// settings so we won't show the dialog.
break;
}
}
});
}
将此案例添加到 onActivityResult 方法中。
case 101:
final LocationSettingsStates states = LocationSettingsStates.fromIntent(data);
switch (resultCode) {
case Activity.RESULT_OK:
// All required changes were successfully made
Log.v("case 101", states.isLocationPresent() + "");
//Everything is good. You can turn on hotspot here.
break;
case Activity.RESULT_CANCELED:
// The user was asked to change settings, but chose not to
Log.v("case 101", "Canceled");
break;
default:
break;
}
break;
我最近创建了一个名为 Spotserve 的演示应用程序。这将为所有 API>=15 的设备打开 WiFi 热点,并在该热点上托管一个演示服务器。您可以检查以获取更多详细信息。希望这有帮助!
关于android - 即使在某些设备上授予所有必需的权限后,调用 WifiManager.startLocalOnlyHotspot() 也会引发 SecurityException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56082255/