我有一个函数,其定义如下:
def expectMsgPF[T](max: Duration = Duration.Undefined, hint: String = "")(f: PartialFunction[Any, T]): T = {
当我这样调用它时:
val res1 = listener1.expectMsgPF(1.second)
res1
是一个函数吗?
我想写如下:
val res1 = listener1.expectMsgPF(1.second) _
val res2 = listener2.expectMsgPF(1.second)
Then("it should contain `Kafka and SAP are offline`")
res1 {
case status: ServerStatus =>
status.health should be(ServersOffline)
}
但是它不起作用。
最佳答案
制作 res1 { case status: ServerStatus => status.health should be(ServersOffline) }
工作,尝试通过提供类型参数 T
来帮助编译器。至expectMsgPF[T]
像这样
val res1 = listener1.expectMsgPF[Assertion](1.second) _
这使得res1
确实是一个类型的函数
PartialFunction[Any, Assertion] => Assertion
关于scala - 无法应用参数化柯里化(Currying)函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56517834/