php - DarkaOnline Swagger-php 生成错误的界面

Question

我目前正在使用 Swagger php 库:https://github.com/DarkaOnLine/L5-Swagger

在我的示例模型类中是这样的:

/** @OA\Schema(
 *    title="ProductPromotion",
 *  @OA\Property(property="id", type="integer"),
 * @OA\Property(property="uid", type="string"),
 * @OA\Property(property="store_id", type="integer"),
 * )
 */
class ProductPromotion extends Model
{
..
}

请注意，我在第三个属性中写了“store_id”。但是当我使用这个jar文件时: openapi-generator-cli-4.1.3，我得到的界面是这样的:

export interface ProductPromotion { 
    id?: number;
    uid?: string;
    storeId?: number;
}

名称从“store_id”更改为“storeId”。我不想要这个，有人知道如何解决这个问题吗？

编辑:用于生成的命令:

java -jar openapi-generator-cli-4.1.3.jar generate -i C:\Users\ASUS\Desktop\OpenAPICodegen\swagger.json -g typescript-angular -o C:\Users\ASUS\Desktop\OpenAPICodegen\dist

Answer 1

也许这可以帮助你:

https://github.com/openapitools/openapi-generator/wiki/FAQ

TypeScript The JSON response failed to deserialize properly into the object due to change in variable naming (snake_case to camelCase). Is there any way to keep the original naming? Yes, please use the following option when generating TypeScript clients:

modelPropertyNaming
    Naming convention for the property: 'camelCase', 'PascalCase', 'snake_case' and 'original', which keeps the original name (Default: camelCase)