javascript - 仅替换相同起始字母字符串之间的逗号

Question

如何仅替换相同起始字母字符串之间的逗号？

这是我所拥有的，部分工作:

const regexA = /(A.+?)(, )(A)/g;
const regexB = /(B.+?)(, )(B)/g;

let value = "A1C, A2, A3B, A4, B1, B2A, B3".replace(regexA, '$1/$3');
value = value.replace(regexB, '$1/$3');
console.log(value); //prints A1C/A2, A3B/A4, B1/B2A, B3

目标:A1C/A2/A3B/A4、B1/B2A/B3

Answer 1

const regexA = /((.)[^,]+), (?=\2|$)/g;

let value = "A1, A2, A3, A4, B1, B2, B3".replace(regexA, '$1/');
console.log(value); 

Demo & explanation