我目前正在开发一个模型,可以在购物时模拟行人的运动。所以,我已经想出了一些我需要的东西,但我一直在试图弄清楚如何在某个补丁中每次蜱释放 2 只海龟(比如一对)。两只海龟同时被释放。我的代码基于 Ant 线,但它只是一次性释放所有行人,然后乌龟开始行走。所有海龟被释放后,蜱虫也会开始出现。我希望海龟进入时就开始“行走”。 这是我的代码:
breed [ leadvisitors leadvisitor ]
breed [ visitors visitor ]
to setup
clear-all
setup-visitors
reset-ticks
end
to setup-visitors
create-leadvisitors num-of-pedestrians * 0.1 ;;create 10% of the total number of pedestrians
[
set demand-type "none"
set color black
set size 1
setxy 0 16
set heading 180
set pen-size 1
set destination one-of patches
set wait-time -1
set demand-lvl 0
]
create-visitors (num-of-pedestrians - (num-of-pedestrians * 0.1))
[ set demand-type 0
set size 1
setxy 0 16
set heading 180
set pen-size 1
set destination one-of patches
set wait-time -1
set demand-lvl 1
set attracted? false
] ]
end
to go
if turtles = 0 [ stop ]
ask turtles
[
set-demand-type
have-demand
]
if ticks > 100 [ stop ]
tick
display-labels
end
;;;;; visitor's internal state of demand ;;;;;
to set-demand-type
if demand-type = 0
[ set demand-type "food"
set color red
let target (patches in-cone visitor-vision-depth visitor-view-angle) with [pcolor = red]
]
end
to have-demand
if demand-lvl = 0
[
ifelse wait-time = -1
[ stroll ]
[ set wait-time wait-time - 1
if wait-time = 0
[ stroll ]]
]
if demand-lvl = 1
[ ifelse wait-time = -1
[ stroll
evaluate ]
[ set wait-time wait-time - 1
if wait-time = 0
[ stroll
evaluate ]]
]
end
to stroll
if any? neighbors with [ pcolor = gray - 3 ]
[ die ]
ifelse any? neighbors with [ pcolor = gray or pcolor = orange or pcolor = blue or pcolor = red]
[ facexy exitpt-x exitpt-y ]
[ rt random-float visitor-view-angle lt random-float visitor-view-angle ]
fd walking-speed
end
to evaluate
if any? neighbors with [ pcolor = gray or pcolor = orange or pcolor = blue or pcolor = gray - 4 or pcolor = gray - 3 or pcolor = red + 2]
[ facexy exitpt-x exitpt-y
rt random-float visitor-view-angle lt random-float visitor-view-angle
fd walking-speed ]
let _mycolor color
if any? (patches in-cone visitor-vision-depth visitor-view-angle) with [pcolor = _mycolor]
[ let new-target max-one-of ( patches with [pcolor = _mycolor] in-cone visitor-vision-depth visitor-view-angle) [patch-influence]
let dist-to-new-target min-one-of (patches with [pcolor = _mycolor] in-cone visitor-vision-depth visitor-view-angle) [distance myself]
face new-target
set heading towards new-target
fd walking-speed
set attracted? true
attracted-and-visiting
re-evaluate
]
end
to attracted-and-visiting
if pcolor = red + 2
[ set heading towards one-of patches with [pcolor = red + 2]
fd 0
set patch-popularity patch-popularity + 1
set wait-time avg-waiting-time
if count turtles-here > 0
[ set num-of-visitors num-of-visitors + 1 ]
set plabel num-of-visitors
]
end
to re-evaluate
let _mycolor color
if not any? (patches in-cone visitor-vision-depth visitor-view-angle) with [pcolor = _mycolor]
[ set attracted? false ]
ifelse choose? [set heading towards one-of patches with [pcolor = _mycolor]] [facexy exitpt-x exitpt-y]
end
to-report choose?
report random 2 = 0
end
最佳答案
根据我们反复评论的结果,让我来看看您正在寻找什么。我假设您想创建 leadvisitors
在运行开始时添加两个 visitors
随着运行的进行,每刻。如果是这样,那么你的setup
程序看起来像
globals [num-visitors-created]
to setup
clear-all
set num-visitors-created 0
create-leadvisitors num-of-pedestrians * 0.1 [
set demand-type "none"
set color black
set size 1
setxy 0 16
set heading 180
set pen-size 1
set destination one-of patches
set wait-time -1
set demand-lvl 0
set num-visitors-created num-visitors-created + 1
]
reset-ticks
end
创建您的leadvisitors
,但没有visitors
。注意全局变量num-visitors-created
跟踪 leadvisitors
的数量和visitors
创建,每次 leadvisitor
时加一或visitor
已创建。
在您的 go
中过程中,您将每次创建两个访问者,直到总数 visitors
和leadvisitors
创建达到num-of-pedestrians
。 (如果只有一个新访客的空间,您是否希望只创建一个,还是需要成对创建它们?我假设是后者。)因为您不希望访客死亡为新的打开空间,我们测试创建的数量,而不是仍然存活的数量。
to go
if turtles = 0 [ stop ]
; create a new pair of visitors if there is room.
if num-visitors-created <= (num-of-pedestrians - 2)
create-visitors 2 [
set demand-type 0
set size 1
set heading 180
set pen-size 1
setxy 0 16
set destination one-of patches
set wait-time -1
set demand-lvl 1
set attracted? false
set num-visitors-created num-visitors-created + 1
]
ask turtles
[
set-demand-type
have-demand
]
if ticks > 100 [ stop ]
tick
display-labels
end
(既然leadvisitors
也可能会死,你是否想保留leadvisitors
的某个最小数量或比例?如果是这样,你应该提出一个新问题。)
上面的代码将创建一对新的 visitors
上patch 0 16
在每个刻度处。但是,如果您想拥有新的 visitors
在不同的补丁上创建,例如红色补丁之一,您可以在 go
中创建程序有那个补丁sprout
新访客。
ask one-of patches with [pcolor = red] [
sprout-visitors 2 [
set demand-type 0
set size 1
set heading 180
set pen-size 1
set destination one-of patches
set wait-time -1
set demand-lvl 1
set attracted? false
set num-visitors-created num-visitors-created + 1
]
]
请注意,此处未设置新访问者的 xy 坐标,因此他们从产生它们的补丁开始。
关于time - 每蜱释放两只海龟 netlogo,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60796907/