嗨,我正在尝试向 https://www.playerup.com/ 发送请求带有打击代码:
import requests
header = {"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.163 Safari/537.36"}
r = requests.get("https://www.playerup.com/",headers=header)
print(r.status_code)
但它给了我一个[503]类型错误 我尝试超时 5 秒,但也不起作用 我应该如何解决它?
最佳答案
因此,使用引用站点和谷歌缓存可以帮助您避免这些失败。所以你的代码应该是:
# here added a referer
header = {"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36" ,'referer':'https://www.google.com/'}
# now use a google cache
r = requests.get("http://webcache.googleusercontent.com/search?q=cache:www.playerup.com/",headers=header)
现在查看状态代码:
>>>r
<Response [200]>
关于python - 响应 503 python 请求,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61346381/