信息。
嘿，:)
我现在学习 Python 几个星期了，刚刚开始一些小项目。现在我正在构建一个脚本来自动化网络浏览器游戏。脚本发出了一些“探险”，这给了我更多的游戏资源。该脚本已经可以运行，但我想改进它。如果您有任何建议，我很想听听。
问题。
我使用 pynput 和 mouse.position = () 来获取要单击的确切位置。有没有办法让点击在某个区域内随机？因为正常人不会总是点击同一个位置。
例如单击这些位置之间的随机位置: 鼠标位置 (2000, 500) 鼠标位置(3000, 1000)
我的脚本。
import pynput, time, random, sys
from pynput.keyboard import Key, Controller as KeyboardController
from pynput.mouse import Button, Controller as MouseController
timeDelay = random.randrange(2, 4)
def locateogame():
#---------------------------------------------> Getting to Ogame.nl
mouse = MouseController()
keyboard = KeyboardController()
mouse.position = (2392, 48)
mouse.click(Button.left, 1)
time.sleep(timeDelay)
keyboard.type("Ogame.nl")
keyboard.press(Key.enter)
keyboard.release(Key.enter)
#login to account and universe.
time.sleep(timeDelay)
mouse.position = (2343, 564)
mouse.click(Button.left, 1)
def p1():
#---------------------------------------------> Locate to planet 1
mouse = MouseController()
time.sleep(timeDelay)
mouse.position = (3054, 298)
mouse.click(Button.left, 1)
def p2():
#---------------------------------------------> Locate to planet 2
#Locate to 5:352:8
mouse = MouseController()
time.sleep(timeDelay)
mouse.position = (3060, 382)
mouse.click(Button.left, 1)
def p3():
#---------------------------------------------> Locate to planet 3
#Locate to 5:353:7
mouse = MouseController()
time.sleep(timeDelay)
mouse.position = (3074, 438)
mouse.click(Button.left, 1)
def p4():
#---------------------------------------------> Locate to planet 4
#Locate to 5:353:8
mouse = MouseController()
time.sleep(timeDelay)
mouse.position = (3073, 481)
mouse.click(Button.left, 1)
def p5():
#---------------------------------------------> Locate to planet 5
#Locate to 4:32:8
mouse = MouseController()
time.sleep(timeDelay)
mouse.position = (3099, 538)
mouse.click(Button.left, 1)
def Sending():
#---------------------------------------------> This will do all the clicking to send my ships
mouse = MouseController()
keyboard = KeyboardController()
#Select Fleet from menu
time.sleep(timeDelay)
mouse.position = (2254, 493)
mouse.click(Button.left, 1)
#select "Expeditie" Fleet
time.sleep(timeDelay)
mouse.position = (2670, 694)
mouse.click(Button.left, 1)
#Expedition
time.sleep(timeDelay)
mouse.position = (2598, 743)
mouse.click(Button.left, 1)
time.sleep(timeDelay)
mouse.position = (2954, 678)
mouse.click(Button.left, 1)
#select slot 16
time.sleep(timeDelay)
mouse.position = (2796, 434)
mouse.click(Button.left, 1)
keyboard.type("16")
keyboard.press(Key.enter)
keyboard.release(Key.enter)
#expeditie button
time.sleep(timeDelay)
mouse.position = (2408, 378)
mouse.click(Button.left, 1)
#send Fleet
time.sleep(timeDelay)
mouse.position = (2862, 711)
mouse.click(Button.left, 1)
##---------------------------------------------> Start of the script.
locateogame()
fns = [p1, p2, p3, p4, p5]
from random import choice
choice(fns)()
Sending()
感谢您的宝贵时间，祝您有美好的一天!
最佳答案
您可以使用random.randint从一个范围中采样一个值。只需执行两次此操作，一次针对您的 X 值，另一次针对 Y 值
>>> import random
>>> random.randint(2000, 3000)
2786
>>> random.randint(500, 1000)
838
所以在你的代码中你可以这样做
from random import randint
mouse.position = (randint(2000, 3000), randint(500, 1000))
关于python - 使用 pynput 在随机位置自动单击鼠标(对于网页浏览器游戏)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/61636521/