linux - 直到循环不适用于 shell 中的字符串比较

Question

在以下 bash shell 脚本中，until 循环无法正常工作。

cm_health_check=$(curl -X GET -u "admin:admin" http://$HOSTNAME:7180/api/v11/cm/service/ | jq '
.entityStatus')
echo $cm_health_check
until [ $cm_health_check -eq "GOOD_HEALTH" ]
do
   cm_health_check=$(curl -X GET -u "admin:admin" http://$HOSTNAME:7180/api/v11/cm/service/ | jq '
.entityStatus')
done

输出

 + curl -X GET -u admin:admin http://abcd.xyz.com:7180/api/v11/cm/service/
   % Total    % Received % Xferd  Average Speed   Time    Time     Time  Current
                                  Dload  Upload   Total   Spent    Left  Speed
 
    0     0    0     0      0      0 --:--:-- --:--:-- --:--:--     0
    0   503    0     0  17023      0 --:--:-- --:--:-- --:--:-- 17344
 "STARTING"
 + echo '"STARTING"'
 + [ '"STARTING"' -eq GOOD_HEALTH ]

until循环不等待状态获得GOOD_HEALTH，我在这里做错了什么？

Answer 1

-eq 运算符用于数字， 而非字符串。对于字符串，您需要 =。如果您查看 bash 文档，您会看到(我的重点):

arg1 OP arg2:

OP is one of -eq, -ne, -lt, -le, -gt, or -ge.

These arithmetic binary operators return true if arg1 is equal to, not equal to, less than, less than or equal to, greater than, or greater than or equal to arg2, respectively.
Arg1 and arg2 may be positive or negative integers.

例如:

pax:~> [[ 'xx' = 'yy' ]] && echo WTF
pax:~> [[ 'xx' -eq 'yy' ]] && echo WTF
WTF