我正在使用 graphviz，但是我想将节点“This on top”强制到页面顶部，而不是侧面。这是图表:
这是代码:
g= Digraph('trial', filename='trial.gv')
g.attr(compound='true', rankdir="TB" )
with g.subgraph() as s:
s.attr(rank='max')
s.node('This on top ')
s.edge('this right under', "Fabrication")
with g.subgraph(name='cluster0') as c:
c.node("This")
c.node("that")
c.node("and this on the same level")
g.edge("this right under","that", lhead="cluster0" )
g.edge("that","This on top ", ltail="cluster0" )
g
是否有命令可以确保节点按我希望的顶部/底部顺序显示？
最佳答案
第一个问题是设置rank='max'会强制第一个子图中的所有内容达到最大排名，即最低排名。您可能打算设置 rank='min' ，这会将子图中的项目置于最高排名，但这仍然无法创建您想要的排列。
相反，您可以通过在创建边缘时设置 style = 'invis' 来使用不可见边缘，以强制“This on top”位于“this right under”之前。
from graphviz import Digraph
g= Digraph('trial', filename='trial.gv')
g.attr(compound='true', rankdir="TB" )
with g.subgraph() as s:
# s.attr(rank='min') # you don't need this line
s.node('This on top ')
s.edge('This on top ', 'this right under', style='invis') # add this invisible edge
s.edge('this right under', "Fabrication")
with g.subgraph(name='cluster0') as c:
c.node("This")
c.node("that")
c.node("and this on the same level")
g.edge("this right under", "that", lhead="cluster0" )
g.edge("that", "This on top ", ltail="cluster0", constraint="false" )
g
它产生:
关于python - GRAPHVIZ:强制节点位于页面顶部，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/64297587/