我正在尝试使用列表理解从范围创建嵌套列表。
到目前为止,我编写了它的 for
循环版本。有什么方法可以使用列表理解来做到这一点吗?
这是我的代码:
matrix = []
start = 1
for x in range(11, 51, 10):
item = list(range(start, x))
matrix.append(item)
start = x
[print(row) for row in matrix]
结果:
[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[11, 12, 13, 14, 15, 16, 17, 18, 19, 20]
[21, 22, 23, 24, 25, 26, 27, 28, 29, 30]
[31, 32, 33, 34, 35, 36, 37, 38, 39, 40]]
最佳答案
试试这个:
matrix=[list(range(i*10+1, i*10+11)) for i in range(4)]
>>> print(matrix)
[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], [11, 12, 13, 14, 15, 16, 17, 18, 19, 20], [21, 22, 23, 24, 25, 26, 27, 28, 29, 30], [31, 32, 33, 34, 35, 36, 37, 38, 39, 40]]
关于python - 使用理解和范围创建嵌套,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/64705362/