python - 将 2D 点云双线性加权到网格上的最快方法

Question

给定一个点 (0.8, 0.6) 和强度 (3)，可以将单个点双线性“反向插值”到具有整数的 2x2 网格上索引(0,0) -> (1,1)。

点和网格的方向是第一个条目向下增加，第二个条目向右增加。

在这样的网格上，上面坐标的权重变为:

  0.08 |  0.12  
----------------
  0.32 |  0.48

我们可以乘以与坐标相关的强度，得到 2x2 网格双线性加权强度:

  0.24 |  0.36 
----------------
  0.96 |  1.44

可以这样绘制:

对于几个点，可以将它们权衡到同一个数组上(完整代码如下):

points = np.array([(0.8, 0.6), (2.2, 2.6),(5, 1), (3, 4.2), (8.5, 8.2)])
intens = np.array([3, 3, 1, 1, 2])
image, weight = bilinear(points, intens)

对于我的工作，我需要 weights 和 intensity*weights 作为输出数组。我需要对大量(数百万)坐标执行上述操作，其中坐标的值从 0.0 到 4095.0。我在下面编写了一个 numpy 例程，虽然对于 100_000 个点来说它相当快(1.25 秒)，但我希望它更快，因为我需要在我拥有的 10_000_000 个数据点上多次调用它。

我考虑对 numpy 代码进行矢量化而不是 for 循环，但随后我为每个点生成一个 4096x4096 大部分为空的数组，然后我将对其求和。这将需要 1000 TB 的内存。

我也在 cupy 中尝试过简单的实现，但由于我使用了 for 循环，它变得太慢了。

在我的代码中，我为每个点生成一个 2x2 加权数组，将该数组乘以强度，然后通过切片将它们添加到主数组中。有更好的办法吗？

import numpy as np

def bilinear(points, intensity):
    """Bilinear weighting of points onto a grid.
    Extent of grid given by min and max of points in each dimension
    points should have shape (N, 2)
    intensity should have shape (N,)
    """
    floor = np.floor(points)
    ceil = floor + 1
    floored_indices = np.array(floor, dtype=int)
    low0, low1 = floored_indices.min(0)
    high0, high1 = floored_indices.max(0)
    floored_indices = floored_indices - (low0, low1)
    shape = (high0 - low0 + 2, high1-low1 + 2)
    
    weights_arr = np.zeros(shape, dtype=float)
    int_arr = np.zeros(shape, dtype=float)
    
    upper_diff = ceil - points
    lower_diff = points - floor
    w1 = np.prod((upper_diff), axis=1)
    w2 = upper_diff[:,0]*lower_diff[:,1]
    w3 = lower_diff[:,0]*upper_diff[:,1]
    w4 = np.prod((lower_diff), axis=1)
    
    for i, index in enumerate(floored_indices):
        s = np.s_[index[0]:index[0]+2, index[1]:index[1]+2]
        weights = np.array([[w1[i], w2[i]], [w3[i], w4[i]]])
        weights_arr[s] += weights
        int_arr[s] += intensity[i]*weights
    return int_arr, weights_arr

rng = np.random.default_rng()
N_points = 10_000 #  use 10_000 so it is quick
image_shape = (256, 256) # Use 256 so it isn't so big

points = rng.random((N_points, 2)) * image_shape
intensity = rng.random(N_points)

image, weight = bilinear(points, intensity)

为了测试代码，我还提供了以下绘图代码 - 仅使用少量(~10)个点，否则散点将覆盖整个图像。

import matplotlib.pyplot as plt
floor = np.floor(points) - 0.5
lower, left = floor.min(0)
upper, right = (floor).max(0) + 2
extent = (left, right, upper, lower)

fig, (ax1, ax2) = plt.subplots(ncols=2, figsize=(6,3))
ax1.scatter(*points[:,::-1].T, c='red')
im1 = ax1.imshow(weight, clim=(image.min(), image.max()), extent=extent)
ax1.set(title='Weight', xlim=(left - 1, right + 1), ylim = (upper + 1, lower - 1))
colorbar(im1)

ax2.scatter(*points[:,::-1].T , c='red')
im2 = ax2.imshow(image, extent=extent)

ax2.set(title='Weight x Intensity', xlim=(left - 1, right + 1), ylim = (upper + 1, lower - 1))
colorbar(im2)
plt.tight_layout()
plt.show()

# If labeling the first point
# ax1.text(*points[0].T, f"({points[0,0]}, {points[0,1]})", va='bottom', ha='center', color='red')
# ax2.text(*points[0].T, f"({points[0,0]}, {points[0,1]}, {intens[0]})", va='bottom', ha='center', color='red')

Answer 1

您需要使用np.add.at。请参阅，https://numpy.org/doc/stable/reference/generated/numpy.ufunc.at.html

def bilinear_2(points, intensity):
    # Create empty matrices, starting from 0 to p.max
    w = np.zeros((points[:, 0].max().astype(int) + 2, points[:, 1].max().astype(int) + 2))
    i = np.zeros_like(w)
    
    # Calc weights
    floor = np.floor(points)
    ceil = floor + 1
    upper_diff = ceil - points
    lower_diff = points - floor
    w1 = upper_diff[:, 0] * upper_diff[:, 1]
    w2 = upper_diff[:, 0] * lower_diff[:, 1]
    w3 = lower_diff[:, 0] * upper_diff[:, 1]
    w4 = lower_diff[:, 0] * lower_diff[:, 1]
    
    # Get indices
    ix, iy = floor[:, 0].astype(int), floor[:, 1].astype(int)

    # Use np.add.at. See, https://numpy.org/doc/stable/reference/generated/numpy.ufunc.at.html
    np.add.at(w, (ix, iy), w1)
    np.add.at(w, (ix, iy+1), w2)
    np.add.at(w, (ix+1, iy), w3)
    np.add.at(w, (ix+1, iy+1), w4)

    np.add.at(i, (ix, iy), w1 * intensity)
    np.add.at(i, (ix, iy+1), w2 * intensity)
    np.add.at(i, (ix+1, iy), w3 * intensity)
    np.add.at(i, (ix+1, iy+1), w4 * intensity)
    
    # Clip (to accomodate image size to be the same as your bilinear function)
    iix, iiy = points[:, 0].min().astype(int), points[:, 1].min().astype(int)
    i, w = i[iix:, iiy:], w[iix:, iiy:]
    return i, w

# At 10_000 samples:
%time image, weight = bilinear(points, intensity)
%time image_2, weight_2 = bilinear_2(points, intensity)
>>>
CPU times: user 178 ms, sys: 3.73 ms, total: 182 ms
Wall time: 185 ms
CPU times: user 9.63 ms, sys: 601 µs, total: 10.2 ms
Wall time: 10 ms

# These tests passes
np.testing.assert_allclose(weight, weight_2)
np.testing.assert_allclose(image, image_2)

# At 100K samples
N_points = 100_000
image_shape = (256, 256)
points = rng.random((N_points, 2)) * image_shape
intensity = rng.random(N_points)

%time image_2, weight_2 = bilinear_2(points, intensity)

CPU times: user 115 ms, sys: 66 ms, total: 181 ms
Wall time: 181 ms


# At 10M samples
N_points = 10_000_000
image_shape = (256, 256)
points = rng.random((N_points, 2)) * image_shape
intensity = rng.random(N_points)

%time image_2, weight_2 = bilinear_2(points, intensity)

CPU times: user 8.23 s, sys: 656 ms, total: 8.88 s
Wall time: 9.31 s

除此之外，使用这种方法是不可能的。因为整数数组索引不会增量更新。

例如，

a = np.zeros(5)
a[np.array((1,1,2))] += 1
a
>>> array([0., 1., 1., 0., 0.])

但是；

a = np.zeros(5)
np.add.at(a, ([1,1,2]), 1)
a
>>> array([0., 2., 1., 0., 0.])