python - Django-Graphene : On a model ChoiceField, graphene 需要一个类型但得到一个值

Question

在 Django-Graphene 上，我有这个模型:

class Entry(models.Model):
    STATE_CHOICES = [
        ("Open", "Open"),
        ("Processing", "Processing"),
        ("Closed", "Closed"),
        ("Deleted", "Deleted"),
    ]

    # ...
    state = models.CharField(max_length=10, choices=STATE_CHOICES,
                             default="Open")

具有以下 Graphite 烯架构:

class EntryType(DjangoObjectType):
    class Meta:
        model = models.Entry

class Query(graphene.ObjectType):
    entries = graphene.List(EntryType)

    def resolve_entries(self, info):
        return models.Entry.objects.all()

但是当我使用下一个查询时:

query AllEntries{
  entries{
    id
    state
  }
}

我收到此错误:

{
  "errors": [
    {
      "message": "Expected a value of type \"EntryState\" but received: OPEN",
      "path": [
        "entries",
        1,
        "state"
      ]
    }
  ],
}

有人可以解释一下我做错了什么吗？

Answer 1

这是因为这一行:

state = models.CharField(max_length=10, choices=STATE_CHOICES, default="Open")

即使这被 ORM 接受并正确保存在数据库中，它也会使 Graphite 烯感到困惑，因为它试图将字符串与枚举值进行比较。

要解决这个问题，您可以这样做:

state = models.CharField(max_length=10, choices=STATE_CHOICES, default=STATE_CHOICES.Open)

如果您不想创建/执行迁移，您也可以创建一个 Graphite 烯 ENUM 类型，然后将其映射到您的 resolve_state 函数中。