我正在尝试解析 json 文件并使用 php 在表中显示其内容，但由于某种原因我得到了(注意:未定义的属性:z.json 中的 stdClass::$management_status)
这是我的 json 文件 (z.json) 中的完整示例:
{
"metadata": {
"total_record_count": "1"
},
"devices": [
{
"managed_status": "2",
"device_id": "63225421111",
"is_supervised": true,
"os_version": "10",
"is_lost_mode_enabled": false,
"serial_number": "77898789",
"device_type": "1",
"owned_by": "1",
"is_removed": "false",
"product_name": "TC26",
"device_name": "[email protected]",
"platform_type": "android",
"located_time": "1623936014747",
"imei": [
"352714110033545"
],
"model": "TC26",
"customer_name": "Customer1",
"customer_id": "10489000000041017",
"udid": "95bd2e6ca8654910",
"last_contact_time": "1624254859593",
"platform_type_id": "2",
"user": {
"user_email": "[email protected]",
"user_id": "556654548",
"user_name": "[email protected]"
},
"device_capacity": "17.34"
}
],
"delta-token": "aHR0cHM6Ly9tZG0ubWFuYWdlZW5naW5lLmV1L2FwaS92MS9kZXZpY2VzOjoxNjI0MjU1NzA2NDI4"
}
and here is my php script:
<?php
$json=file_get_contents('z.json');
$data=json_decode($json);
?>
<table>
<tr>
<td>managed_status</td>
<td>device_id</td>
<td>is_supervised</td>
<td>os_version</td>
</tr>
<?php foreach($data as $key=>$item): ?>
<tr>
<td><?PHP echo $item->managed_status ; ?></td>
<td><?PHP echo $item->device_id; ?></td>
<td><?PHP echo $item->is_supervised; ?></td>
<td><?PHP echo $item->os_version; ?></td>
</tr>
<?php endforeach; ?>
</table>
最佳答案
在 foreach 条件中，您尝试迭代日期，需要将其替换为 $data->devices。
<?php
$json = file_get_contents('z.json');
$data = json_decode($json);
?>
<tr>
<td>managed_status</td>
<td>device_id</td>
<td>is_supervised</td>
<td>os_version</td>
</tr>
<?php foreach($data->devices as $key => $item): ?>
<tr>
<td><?php echo $item->managed_status ; ?></td>
<td><?php echo $item->device_id; ?></td>
<td><?php echo $item->is_supervised; ?></td>
<td><?php echo $item->os_version; ?></td>
</tr>
<?php endforeach; ?>
关于php - 错误未定义属性 : stdClass while trying to parse json file in php，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/68079622/