我有一个字典列表
list_ = [
{'id': '1', 'name': 'ABC', 'email': '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="3e5f5c5d7e59535f5752105d5153" rel="noreferrer noopener nofollow">[email protected]</a>', 'role': 'Tester'},
{'id': '2', 'name': 'CDE', 'email': '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="0c6f68694c6b616d6560226f6361" rel="noreferrer noopener nofollow">[email protected]</a>', 'role': 'Developer'},
{'id': '3', 'name': 'fgh', 'email': '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="cdabaaa58daaa0aca4a1e3aea2a0" rel="noreferrer noopener nofollow">[email protected]</a>', 'role': 'Developer'},
{'id': '2', 'name': 'CDE', 'email': '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="3a595e5f7a5d575b535614595557" rel="noreferrer noopener nofollow">[email protected]</a>', 'role': 'Tester'},
{'id': '1', 'name': 'ABC', 'email': '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="fc9d9e9fbc9b919d9590d29f9391" rel="noreferrer noopener nofollow">[email protected]</a>', 'role': 'Developer'}
]
我正在尝试从与 key 匹配的列表中提取特定的角色。
开发人员 的优先级高于测试人员。如果对于特定 ID，同时存在 Developer 和 Tester，则输出应为 Developer。
但是，如果列表中首先出现的是 Tester，那么我的代码将无法工作，它将给出 Tester 而不是 Developer。
我怎样才能正确地做到这一点？我需要添加 break 语句吗？
def find_role(id_, list_):
role = 'user'
for each in list_:
if id_ == each['id'] and each['role'] == 'Developer':
role = 'Developer'
return role
if id_ == each['id'] and each['role'] == 'Tester':
role = 'Tester'
return role
return role
find_role('1', list_)
最佳答案
您当前的脚本不评估角色优先级。相反，它会返回您选择的角色集中的第一个角色。
def find_role(id_, list_):
role = 'user'
for each in list_:
if id_ == each['id']:
# check for first role priority
if each['role'] == 'Developer':
role = 'Developer'
# if first role priority has not been assigned, check for next
elif role != 'Developer' and each['role'] == 'Tester':
role = 'Tester'
return role
find_role('1', list_)
关于python - 如何从列表中优先提取多个匹配值之一？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/68286732/