javascript - 正则表达式匹配句子中的字符串

Question

我试图在句子中找到严格声明的字符串，线程说:

Find the position of the string "ten" within a sentence, without using the exact string directly (this can be avoided in many ways using just a bit of RegEx). Print as many spaces as there were characters in the original sentence before the aforementioned string appeared, and then the string itself in lowercase.

我已经走到这一步了:

let words = 'A ton of tunas weighs more than ten kilograms.'

function findTheNumber(){

         let regex=/t[a-z]*en/gi;
         let output = words.match(regex)
         console.log(words)
         console.log(output) 
}

console.log(findTheNumber())

结果应该是:

input  = A ton of tunas weighs more than ten kilograms.
output =                                 ten(ENTER)           

Answer 1

您可以在回调函数的帮助下尝试正则表达式替换方法:

var input = "A ton of tunas weighs more than ten kilograms.";
var output = input.replace(/\w+/g, function(match, contents, offset, input_string)
{
    if (!match.match(/^[t][e][n]$/)) {
        return match.replace(/\w/g, " ");
    }
    else {
        return match;
    }
});
console.log(input);
console.log(output);

上述逻辑匹配输入句子中的每个单词，然后有选择地将每个不是 10 的单词替换为相同数量的空格。