我正在使用 survminer
包尝试为具有 5 个感兴趣子组的纵向学生级数据集生成生存和危险函数图。
我已经成功创建了一个模型,该模型显示了生存函数,无需使用 ggsurvplot
调整学生级别的协变量。
ggsurvplot(survfit(Surv(expectedgr, sped) ~ langstatus_new, data=mydata), pvalue=TRUE)
但是,我无法设法根据协变量调整这些曲线。我的目标是创建graphs like these 。正如您所看到的,这些是根据某些因子变量进行协变量调整的生存曲线。有人知道如何在R
中获得这样的图表吗?
最佳答案
您希望从 Cox 模型中获取某些感兴趣协变量的某些值的生存概率,同时调整其他协变量。然而,由于我们没有对 Cox 模型中的生存时间分布做出任何假设,因此我们无法直接从中获得生存概率。我们首先必须估计基线风险函数,这通常是使用非参数 Breslow 估计器完成的。当 Cox 模型安装 coxph
时来自survival
包中,我们可以通过调用 survfit()
来获得这样的概率功能。您可以咨询?survfit.coxph
了解更多信息。
让我们看看如何使用 lung
来做到这一点数据集。
library(survival)
# select covariates of interest
df <- subset(lung, select = c(time, status, age, sex, ph.karno))
# assess whether there are any missing observations
apply(df, 2, \(x) sum(is.na(x))) # 1 in ph.karno
# listwise delete missing observations
df <- df[complete.cases(df), ]
# Cox model
fit <- coxph(Surv(time, status == 2) ~ age + sex + ph.karno, data = df)
## Note that I ignore the fact that ph.karno does not satisfy the PH assumption.
# specify for which combinations of values of age, sex, and
# ph.karno we want to derive survival probabilies
ND1 <- with(df, expand.grid(
age = median(age),
sex = c(1,2),
ph.karno = median(ph.karno)
))
ND2 <- with(df, expand.grid(
age = median(age),
sex = 1, # males
ph.karno = round(create_intervals(n_groups = 3L))
))
# Obtain the expected survival times
sfit1 <- survfit(fit, newdata = ND1)
sfit2 <- survfit(fit, newdata = ND2)
函数背后的代码create_intervals()
可以在 this post 中找到。我只是简单地替换了speed
与 ph.karno
在函数中。
输出sfit1
包含 ND1
中指定的协变量组合的预期中位生存时间和相应的 95% 置信区间。 .
> sfit1
Call: survfit(formula = fit, newdata = ND)
n events median 0.95LCL 0.95UCL
1 227 164 283 223 329
2 227 164 371 320 524
通过 times
获得特定随访时间的生存概率summary()
的参数方法。
# survival probabilities at 200 days of follow-up
summary(sfit1, times = 200)
输出再次包含预期生存概率,但现在经过 200 天的随访,其中 survival1
对应ND1
第一行的预期生存概率,即中位数为 age
的男性和女性患者中位数 ph.karno
.
> summary(sfit1, times = 200)
Call: survfit(formula = fit, newdata = ND1)
time n.risk n.event survival1 survival2
200 144 71 0.625 0.751
与这两个概率相关的 95% 置信限可以从 summary()
中手动提取。 .
sum_sfit <- summary(sfit1, times = 200)
sum_sfit <- t(rbind(sum_sfit$surv, sum_sfit$lower, sum_sfit$upper))
colnames(sum_sfit) <- c("S_hat", "2.5 %", "97.5 %")
# ------------------------------------------------------
> sum_sfit
S_hat 2.5 % 97.5 %
1 0.6250586 0.5541646 0.7050220
2 0.7513961 0.6842830 0.8250914
如果您想使用ggplot
描述 ND1
中指定的值组合的预期生存概率(以及相应的 95% 置信区间)和ND2
,我们首先需要制作data.frame
以适当的格式包含所有信息。
# function which returns the output from a survfit.object
# in an appropriate format, which can be used in a call
# to ggplot()
df_fun <- \(surv_obj, newdata, factor) {
len <- length(unique(newdata[[factor]]))
out <- data.frame(
time = rep(surv_obj[['time']], times = len),
n.risk = rep(surv_obj[['n.risk']], times = len),
n.event = rep(surv_obj[['n.event']], times = len),
surv = stack(data.frame(surv_obj[['surv']]))[, 'values'],
upper = stack(data.frame(surv_obj[['upper']]))[, 'values'],
lower = stack(data.frame(surv_obj[['lower']]))[, 'values']
)
out[, 7] <- gl(len, length(surv_obj[['time']]))
names(out)[7] <- 'factor'
return(out)
}
# data for the first panel (A)
df_leftPanel <- df_fun(surv_obj = sfit1, newdata = ND1, factor = 'sex')
# data for the second panel (B)
df_rightPanel <- df_fun(surv_obj = sfit2, newdata = ND2, factor = 'ph.karno')
现在我们已经定义了 data.frame
s,我们需要定义一个新函数来绘制 95% CI。我们为其指定通用名称 geom_stepribbon
.
library(ggplot2)
# Function for geom_stepribbon
geom_stepribbon <- function(
mapping = NULL,
data = NULL,
stat = "identity",
position = "identity",
na.rm = FALSE,
show.legend = NA,
inherit.aes = TRUE, ...) {
layer(
data = data,
mapping = mapping,
stat = stat,
geom = GeomStepribbon,
position = position,
show.legend = show.legend,
inherit.aes = inherit.aes,
params = list(na.rm = na.rm, ... )
)
}
GeomStepribbon <- ggproto(
"GeomStepribbon", GeomRibbon,
extra_params = c("na.rm"),
draw_group = function(data, panel_scales, coord, na.rm = FALSE) {
if (na.rm) data <- data[complete.cases(data[c("x", "ymin", "ymax")]), ]
data <- rbind(data, data)
data <- data[order(data$x), ]
data$x <- c(data$x[2:nrow(data)], NA)
data <- data[complete.cases(data["x"]), ]
GeomRibbon$draw_group(data, panel_scales, coord, na.rm = FALSE)
}
)
最后,我们可以绘制 ND1
的预期生存概率和ND2
.
yl <- 'Expected Survival probability\n'
xl <- '\nTime (days)'
# left panel
my_colours <- c('blue4', 'darkorange')
adj_colour <- \(x) adjustcolor(x, alpha.f = 0.2)
my_colours <- c(
my_colours, adj_colour(my_colours[1]), adj_colour(my_colours[2])
)
left_panel <- ggplot(df_leftPanel,
aes(x = time, colour = factor, fill = factor)) +
geom_step(aes(y = surv), size = 0.8) +
geom_stepribbon(aes(ymin = lower, ymax = upper), colour = NA) +
scale_colour_manual(name = 'Sex',
values = c('1' = my_colours[1],
'2' = my_colours[2]),
labels = c('1' = 'Males',
'2' = 'Females')) +
scale_fill_manual(name = 'Sex',
values = c('1' = my_colours[3],
'2' = my_colours[4]),
labels = c('1' = 'Males',
'2' = 'Females')) +
ylab(yl) + xlab(xl) +
theme(axis.text = element_text(size = 12),
axis.title = element_text(size = 12),
legend.text = element_text(size = 12),
legend.title = element_text(size = 12),
legend.position = 'top')
# right panel
my_colours <- c('blue4', 'darkorange', '#00b0a4')
my_colours <- c(
my_colours, adj_colour(my_colours[1]),
adj_colour(my_colours[2]), adj_colour(my_colours[3])
)
right_panel <- ggplot(df_rightPanel,
aes(x = time, colour = factor, fill = factor)) +
geom_step(aes(y = surv), size = 0.8) +
geom_stepribbon(aes(ymin = lower, ymax = upper), colour = NA) +
scale_colour_manual(name = 'Ph.karno',
values = c('1' = my_colours[1],
'2' = my_colours[2],
'3' = my_colours[3]),
labels = c('1' = 'Low',
'2' = 'Middle',
'3' = 'High')) +
scale_fill_manual(name = 'Ph.karno',
values = c('1' = my_colours[4],
'2' = my_colours[5],
'3' = my_colours[6]),
labels = c('1' = 'Low',
'2' = 'Middle',
'3' = 'High')) +
ylab(yl) + xlab(xl) +
theme(axis.text = element_text(size = 12),
axis.title = element_text(size = 12),
legend.text = element_text(size = 12),
legend.title = element_text(size = 12),
legend.position = 'top')
# composite plot
library(ggpubr)
ggarrange(left_panel, right_panel,
ncol = 2, nrow = 1,
labels = c('A', 'B'))
输出
解释
- 图 A 显示男性和女性患者的预期生存概率中位数
age
中位数ph.karno
. - B 组显示三名男性患者的预期生存概率,中位数
age
与ph.karno
s 为 67(低)、83(中)和 100(高)。
这些生存曲线将始终满足 PH 假设,因为它们是从 Cox 模型导出的。
注意:使用function(x)
而不是\(x)
如果您使用 R <4.1.0
关于r - 如何生成协变量调整的 cox 生存/风险函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/70783093/