javascript - 根据列值将一张 Google 工作表拆分为多张工作表 - 替换重复工作表

Question

这超出了我的知识水平，我希望得到帮助。下面的脚本有一些限制。此脚本检查区域选项卡是否存在，如果不存在，则源工作表中的区域数据将按该区域的名称复制到新选项卡。区域是源工作表上的第 24 列，数据从第 3 行开始，标题是第 2 行。

如果区域选项卡已存在，我希望将其删除，重新创建或使用当前数据重新填充，而不是跳过它。

function createSheets(){

const ss = SpreadsheetApp.getActiveSpreadsheet()
const sourceWS = ss.getSheetByName("Forecast (SQL) Validation")

const regions = sourceWS
  .getRange(3,24,sourceWS.getLastRow()-2,1)
  .getValues()
  .map(rng => rng[0])

const uniqueRegion = [ ...new Set(regions) ]

const currentSheetNames = ss.getSheets().map(s => s.getName())

let ws

uniqueRegion.forEach(region => {

  if(!currentSheetNames.includes(region)){

    ws = null
    ws = ss.insertSheet()
    ws.setName(region)
    ws.getRange("A2").setFormula(`=FILTER('Forecast (SQL) Validation'!A3:CR,'Forecast (SQL) Validation'!X3:X="${region}")`)
    sourceWS.getRange("A2:CR2").copyTo(ws.getRange("A1:CR1"))

}//If regions doesn't exist

})//forEach loop through the list of region

} //close createsheets functions

Answer 1

这样试试

function createSheets() {
  const ss = SpreadsheetApp.getActive()
  const ssh = ss.getSheetByName("Forecast (SQL) Validation");
  const regions = ssh.getRange(3, 24, ssh.getLastRow() - 2, 1).getValues().flat();
  const urA = [...new Set(regions)];
  const shnames = ss.getSheets().map(s => s.getName())
  let ws;
  urA.forEach(region => {
    let idx = shnames.indexOf(region);
    if (~idx) {
      ss.deleteSheet(ss.getSheetByName(shnames(idx)));//if it does exist delete it and create a new one
    }//if it does not exist the just create a new one
    ws = null;
    ws = ss.insertSheet(region);
    ws.getRange("A2").setFormula(`=FILTER('Forecast (SQL) Validation'!A3:CR,'Forecast (SQL) Validation'!X3:X="${region}")`)
    ssh.getRange("A2:CR2").copyTo(ws.getRange("A1:CR1"))
  })
}

说明:

循环遍历所有选项卡，如果该选项卡已经存在，则通过 deleteSheet 删除它在再次创建它之前，就像您对不存在的那些所做的那样..