我有一个如下的 pandas 系列，它代表距该点的距离。
[53.14215611146749,
68.38785810979309,
73.39766970890767,
62.55809054344587,
61.65664511406602,
67.30027137647377,
53.18713806914155,
44.731280834334726,
56.775601188099564,
48.70050608722388,
52.058305375893326,
43.86576801918336,
40.7737929704101,
48.14255989609582,
66.1008274224399,
64.14163441281926,
74.19664861255285,
39.2240226739306,
43.19696483020877,
56.19908015933838,
52.75637095625348,
72.94738557673514,
68.43340406723989,
55.3282335432387,
14.063542002183079,
65.42855719150613,
64.57283331956563,
55.7359195807484,
46.47999444513133,
67.90377608318023,
45.20662678388409,
60.89180227702483,
55.498083875456516,
66.27610947615794,
22.845312320987933,
55.68089486356418,
37.17249970361574,
31.996833503627055,
8.004580252301615,
57.701300278758396,
55.68491218953833,
49.69553182988371,
62.857799532025695,
64.4881255962942,
56.52268246645304,
53.70335480184844,
47.68999060768484,
70.19624652173587,
46.06795699534889,
43.10099872431838,
39.554771098646285,
39.35671580350949,
63.702434120074344,
63.97772732522319,
55.721880827686036,
40.45931808597496,
54.21292609875884,
16.675696857750737,
41.39693209332469,
54.254194394652124,
20.35367440002031,
59.334225047181775,
54.27213837753601,
71.06412120928913,
32.77778238532229,
44.525878012920465,
21.633778938745873,
62.82994949086467,
53.74149464908078,
43.55381629902706,
62.06565329192727,
60.84255535670013,
69.61908591774456,
62.42694740156783,
24.305272369346792,
53.67321288616061,
41.51862527126106,
53.06105426101688,
52.29598013335814,
56.56807611441198,
54.44050075253376,
69.0021067468377,
51.62347224748836,
52.22881959386345,
46.864584528474325,
47.012472881260116,
51.646519289015345,
45.619767144941775,
8.519681182197928,
68.36194018083505,
24.231287660834653,
54.903970823297854,
38.8830383852113,
60.93359558626832,
60.20955222539125,
49.42302250000802,
44.393460251409024,
41.81242566960246,
56.712784485916885,
19.378568603967558]
现在，我需要在这 100 个数字中分配一个数字(例如 15)。
如果距离较小，则应获得较大的比例 15。如果距离较大，则应获得较小的比例 15。
即 14.063542002183079 的输出应该获得更大的比例(因为它更近)，而 53.14215611146749 应该变得更小(因为它更远)
但是，100 个派生数字的总和应该为 15(即值 15 根据距离分配)。
到目前为止我已经尝试过
我使用softmax函数将这些距离数字(100个列表)转换为0和1之间。
将列表中的每个数字乘以 15。现在，列表中的数字之和为 15。但这些值不是根据距离分布的。
最佳答案
N = 15
dists = 1 / (s - N).abs()
weights = dists / dists.sum()
result = weights * N
- 找到与 N 的绝对差的距离，但倒数越近越好
- 通过归一化距离求和来获取权重
- 为 N 分配权重
关于python - 根据距离分配值(value) - pandas，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/73831011/