我的一项服务在 4 个不同的位置出现中断。我正在将每个位置的中断建模到一个 Boost ICL interval_set 中。我想知道至少 N 个位置何时发生事件中断。
因此,关注this answer ,我已经实现了组合算法,因此我可以通过 interval_set 交集在元素之间创建组合。
当这个过程结束时,我应该有一定数量的 interval_set,它们中的每一个同时定义 N 个位置的中断,最后一步将加入它们以获得所需的全貌。
问题是我目前正在调试代码,当打印每个交叉点的时间到了时,输出的文本变得疯狂(即使我正在使用 gdb 逐步调试),我无法看到它们,导致大量的 CPU 使用率。
我想我以某种方式发送输出的内存比我应该的要多,但我看不出问题出在哪里。
这是一个 SSCCE:
#include <boost/icl/interval_set.hpp>
#include <algorithm>
#include <iostream>
#include <vector>
int main() {
// Initializing data for test
std::vector<boost::icl::interval_set<unsigned int> > outagesPerLocation;
for(unsigned int j=0; j<4; j++){
boost::icl::interval_set<unsigned int> outages;
for(unsigned int i=0; i<5; i++){
outages += boost::icl::discrete_interval<unsigned int>::closed(
(i*10), ((i*10) + 5 - j));
}
std::cout << "[Location " << (j+1) << "] " << outages << std::endl;
outagesPerLocation.push_back(outages);
}
// So now we have a vector of interval_sets, one per location. We will combine
// them so we get an interval_set defined for those periods where at least
// 2 locations have an outage (N)
unsigned int simultaneusOutagesRequired = 2; // (N)
// Create a bool vector in order to filter permutations, and only get
// the sorted permutations (which equals the combinations)
std::vector<bool> auxVector(outagesPerLocation.size());
std::fill(auxVector.begin() + simultaneusOutagesRequired, auxVector.end(), true);
// Create a vector where combinations will be stored
std::vector<boost::icl::interval_set<unsigned int> > combinations;
// Get all the combinations of N elements
unsigned int numCombinations = 0;
do{
bool firstElementSet = false;
for(unsigned int i=0; i<auxVector.size(); i++){
if(!auxVector[i]){
if(!firstElementSet){
// First location, insert to combinations vector
combinations.push_back(outagesPerLocation[i]);
firstElementSet = true;
}
else{
// Intersect with the other locations
combinations[numCombinations] -= outagesPerLocation[i];
}
}
}
numCombinations++;
std::cout << "[-INTERSEC-] " << combinations[numCombinations] << std::endl; // The problem appears here
}
while(std::next_permutation(auxVector.begin(), auxVector.end()));
// Get the union of the intersections and see the results
boost::icl::interval_set<unsigned int> finalOutages;
for(std::vector<boost::icl::interval_set<unsigned int> >::iterator
it = combinations.begin(); it != combinations.end(); it++){
finalOutages += *it;
}
std::cout << finalOutages << std::endl;
return 0;
}
有什么帮助吗?
最佳答案
作为I surmised ,这里有一个“高级”方法。
Boost ICL 容器不仅仅是“美化的间隔起点/终点对”的容器。它们旨在以一般优化的方式实现只是组合、搜索的业务。
因此您不必这样做。
如果你让库做它应该做的事:
using TimePoint = unsigned;
using DownTimes = boost::icl::interval_set<TimePoint>;
using Interval = DownTimes::interval_type;
using Records = std::vector<DownTimes>;
使用功能域类型定义需要更高层次的方法。现在,让我们提出假设的“业务问题”:
What do we actually want to do with our records of per-location downtimes?
好吧,我们本质上想要
- 统计所有可识别的时间段,
- 过滤掉计数至少为 2 的那些
- 最后,我们想展示剩余的“合并”时间段。
好的,工程师:实现它!
嗯。理货。它能有多难?
❕ The key to elegant solutions is the choice of the right datastructure
using Tally = unsigned; // or: bit mask representing affected locations? using DownMap = boost::icl::interval_map<TimePoint, Tally>;
现在只是批量插入:
// We will do a tally of affected locations per time slot DownMap tallied; for (auto& location : records) for (auto& incident : location) tallied.add({incident, 1u});
好的,让我们过滤。我们只需要在我们的 DownMap 上起作用的谓词,对吧
// define threshold where at least 2 locations have an outage auto exceeds_threshold = [](DownMap::value_type const& slot) { return slot.second >= 2; };
合并时间段!
其实。我们只是创建另一个停机时间集,对吧。只是,这次不是每个位置。
数据结构的选择再次获胜:
// just printing the union of any criticals: DownTimes merged; for (auto&& slot : tallied | filtered(exceeds_threshold) | map_keys) merged.insert(slot);
举报!
std::cout << "Criticals: " << merged << "\n";
请注意,我们在任何地方都没有接近操纵数组索引、重叠或非重叠间隔、封闭或开放边界。或者,[eeeeek!] 集合元素的强力排列。
我们只是陈述了我们的目标,让图书馆来完成工作。
完整演示
#include <boost/icl/interval_set.hpp>
#include <boost/icl/interval_map.hpp>
#include <boost/range.hpp>
#include <boost/range/algorithm.hpp>
#include <boost/range/adaptors.hpp>
#include <boost/range/numeric.hpp>
#include <boost/range/irange.hpp>
#include <algorithm>
#include <iostream>
#include <vector>
using TimePoint = unsigned;
using DownTimes = boost::icl::interval_set<TimePoint>;
using Interval = DownTimes::interval_type;
using Records = std::vector<DownTimes>;
using Tally = unsigned; // or: bit mask representing affected locations?
using DownMap = boost::icl::interval_map<TimePoint, Tally>;
// Just for fun, removed the explicit loops from the generation too. Obviously,
// this is bit gratuitous :)
static DownTimes generate_downtime(int j) {
return boost::accumulate(
boost::irange(0, 5),
DownTimes{},
[j](DownTimes accum, int i) { return accum + Interval::closed((i*10), ((i*10) + 5 - j)); }
);
}
int main() {
// Initializing data for test
using namespace boost::adaptors;
auto const records = boost::copy_range<Records>(boost::irange(0,4) | transformed(generate_downtime));
for (auto location : records | indexed()) {
std::cout << "Location " << (location.index()+1) << " " << location.value() << std::endl;
}
// We will do a tally of affected locations per time slot
DownMap tallied;
for (auto& location : records)
for (auto& incident : location)
tallied.add({incident, 1u});
// We will combine them so we get an interval_set defined for those periods
// where at least 2 locations have an outage
auto exceeds_threshold = [](DownMap::value_type const& slot) {
return slot.second >= 2;
};
// just printing the union of any criticals:
DownTimes merged;
for (auto&& slot : tallied | filtered(exceeds_threshold) | map_keys)
merged.insert(slot);
std::cout << "Criticals: " << merged << "\n";
}
哪个打印
Location 1 {[0,5][10,15][20,25][30,35][40,45]}
Location 2 {[0,4][10,14][20,24][30,34][40,44]}
Location 3 {[0,3][10,13][20,23][30,33][40,43]}
Location 4 {[0,2][10,12][20,22][30,32][40,42]}
Criticals: {[0,4][10,14][20,24][30,34][40,44]}
关于c++ - N Boost interval_set 的组合,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28319841/