django - 关于 admin.py list_display 的问题

Question

#admin.py
class GameListAdmin(admin.ModelAdmin):
    list_display = ['game', 'position']
    ordering = ('position',)

class GameAdmin(admin.ModelAdmin):
    list_display = ['name', 'status']
    actions = [make_published]

#models.py
class Game(models.Model):
    name = models.CharField(max_length=200)
    status = models.CharField(max_length=1, choices=STATUS_CHOICES)

    def __unicode__(self):
        return self.name

class GameList(models.Model):
    game = models.ForeignKey(Game)
    position = models.IntegerField()

    def __unicode__(self):
        return self.game.name

我试图在 GameListAdmin 的 list_display 中显示 game.status 但没有 确定如何使用 Admin.py 中的foreignkey进行向后查找

有什么想法吗？

Answer 1

你可以这样做:

def get_status(obj):
    return '%s' % (obj.game.status)
get_status.short_description = 'Status'

class GameListAdmin(admin.ModelAdmin):
    list_display = ['game', 'position', get_status]

请参阅docs .