c++ - "hello world"string literal 可以赋给char * 类型吗？

Question

char* foo = "fpp"; //compile in vs 2010 with no problem

虽然字符串文字是 const char* 类型。
const 类型不能赋值给非 const 类型。
所以我希望上面的代码失败或者我遗漏了什么？

编辑:抱歉各位，我完全忘记了编译器也会抛出警告。
我一直在看错误列表。
我忘了检查那个。

Edit2:我将我的项目警告级别设置为 EnableAllWarnings (/Wall)，但没有关于此的警告。
所以我的问题仍然有效。

Answer 1

C++03 反对^{[引用 1]} 使用不带 const 关键字的字符串文字。

^{[引用 1]}C++03 标准:§4.2/2

A string literal (2.13.4) that is not a wide string literal can be converted to an rvalue of type “pointer to char”; a wide string literal can be converted to an rvalue of type “pointer to wchar_t”. In either case, the result is a pointer to the first element of the array. This conversion is considered only when there is an explicit appropriate pointer target type, and not when there is a general need to convert from an lvalue to an rvalue. [Note: this conversion is deprecated. See Annex D. ] For the purpose of ranking in overload resolution (13.3.3.1.1), this conversion is considered an array-to-pointer conversion followed by a qualification conversion (4.4). [Example: "abc" is converted to “pointer to const char” as an array-to-pointer conversion, and then to “pointer to char” as a qualification conversion. ]

C++11 只是删除了上面的引用，这暗示它在 C++11 中是非法代码。

在 C++03 之前，C++ 派生了它的字符串字面量声明而没有 const 关键字，请注意，这在 C 中是完全有效的。