我有以下代码:
preg_match_all('/(.*) \((\d+)\) - ([\d\.\d]+)[,?]/U',
"E-Book What I Didn't Learn At School... (2) - 3525.01, FREE Intro DVD/Vid (1) - 0.15",
$match);
var_dump($string, $match);
并获得以下输出:
array(4) {
[0]=>
array(1) {
[0]=>
string(54) "E-Book What I Didn't Learn At School... (2) - 3525.01,"
}
[1]=>
array(1) {
[0]=>
string(39) "E-Book What I Didn't Learn At School..."
}
[2]=>
array(1) {
[0]=>
string(1) "2"
}
[3]=>
array(1) {
[0]=>
string(7) "3525.01"
}
}
仅匹配一个项目...我需要的是从这些字符串中获取所有项目。当我在字符串末尾添加“,”符号时 - 它工作得很好。但这在每个字符串中添加逗号是没有意义的。有什么建议吗?
最佳答案
尝试这个正则表达式:
(.*?)\s*\((\d+)\)\s*-\s*(\d+\.\d+)(?:,\s*)?
主要区别在于您有 .*
(贪婪),我将其替换为 .*?
(非贪婪)。您首先“吃掉”整个字符串(除了换行符),然后回溯以仅匹配字符串中的一个片段。
演示:
preg_match_all('/(.*?)\s*\((\d+)\)\s*-\s*(\d+\.\d+)(?:,\s*)?/',
"E-Book What I Didn't Learn At School... (2) - 3525.01, FREE Intro DVD/Vid (1) - 0.15",
$matches, PREG_SET_ORDER);
print_r($matches);
产生:
Array
(
[0] => Array
(
[0] => E-Book What I Didn't Learn At School... (2) - 3525.01,
[1] => E-Book What I Didn't Learn At School...
[2] => 2
[3] => 3525.01
)
[1] => Array
(
[0] => FREE Intro DVD/Vid (1) - 0.15
[1] => FREE Intro DVD/Vid
[2] => 1
[3] => 0.15
)
)
关于php - 使用 preg_match_all() 和结束字符匹配一个字符串中的多个项目,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2575124/