awk - 仅使用 awk 和 sed 修改第 2 列

Question

我有一个包含 3 列的列表:

2547123456789,5391074043372870,639027123456789

我想像这样修改第二列:

sed 's/\([0-9]\)\([0-9]\)/\2\1/g' so that it becomes:

3519700434738207

我的问题是如何在 awk/sed 的一行中执行此操作，同时保持其他列不变，以便我的最终文件具有:

2547123456789,3519700434738207,639027123456789

谢谢

Answer 1

试试这个:

sed 'h;s/.*,\([^,]*\),.*/\1/;s/\(.\)\(.\)/\2\1/g;G;s/\([^\n]*\)\n\([^,]*,\)[^,]*\(.*\)/\2\1\3/' inputfile

说明:

# copy the line to hold space
h;
# capture the second column and retain it in pattern space
s/.*,\([^,]*\),.*/\1/;
# swap each pair of characters
s/\(.\)\(.\)/\2\1/g;
# append the contents of hold space, now pattern space looks like
# new_field_2[newline]field_1,old_field_2,field_3
G;
# capture the fields that we want and arrange them in the proper order
s/\([^\n]*\)\n\([^,]*,\)[^,]*\(.*\)/\2\1\3/