sql - ORACLE SQL 如果另一个时间戳不在此范围内，则显示所有日期/时间范围

Question

一个表DT具有不同的时间戳:

日期时间

22/01/2013 22:30
16/10/2012 11:20
30/03/2012 20:50

另一个带有开始日期和结束日期的表时间框架:

SDT                     EDT
22/01/2013 23:30        22/01/2013 23:40
22/01/2013 20:30        22/01/2013 20:40  
22/01/2013 22:10    X   22/01/2013 22:40 <--should filtered out because
                                            one of the timestamps(values from DT table)
                                            is between SDT & EDT
16/10/2012 11:00        16/10/2012 11:10
16/10/2012 11:00    X   16/10/2012 11:40 <--should filtered out because
                                            one of the timestamps(values from DT table)
                                            is between SDT & EDT

因此，所需的结果将是 TIMEFRAMES 表中的所有行，除了 DT 表中的任何时间戳 (date_time) 不落在表 TIMEFRAMES 的时间范围之间的行

SDT                   EDT
22/01/2013 23:30      22/01/2013 23:40
22/01/2013 20:30      22/01/2013 20:40    
16/10/2012 11:00      16/10/2012 11:10

http://www.sqlfiddle.com/#!4/340a8/3

Answer 1

尝试:

select * from timeframes f where not exists
(select 1 from dt where dt.date_time between f.sdt and f.edt)