我不知道这是否会被正式称为枢轴,但我想要的结果是这样的:
+------+---------+------+
| Alex | Charley | Liza |
+------+---------+------+
| 213 | 345 | 1 |
| 23 | 111 | 5 |
| 42 | 52 | 2 |
| 323 | | 5 |
| 23 | | 1 |
| 324 | | 5 |
+------+---------+------+
我的输入数据采用以下形式:
+-----+---------+
| Apt | Name |
+-----+---------+
| 213 | Alex |
| 23 | Alex |
| 42 | Alex |
| 323 | Alex |
| 23 | Alex |
| 324 | Alex |
| 345 | Charley |
| 111 | Charley |
| 52 | Charley |
| 1 | Liza |
| 5 | Liza |
| 2 | Liza |
| 5 | Liza |
| 1 | Liza |
| 5 | Liza |
+-----+---------+
因为我有大约 100 个名称,所以我不想像这样执行大量子查询
select null, null, thirdcolumn from...
select null, seconcolumn from...
select firstcolumn from...
有没有办法通过PIVOT
或其他方式来做到这一点?
最佳答案
您可以使用动态 PIVOT
和 ROW_NUMBER()
函数来完成此操作:
DECLARE @cols AS VARCHAR(1000),
@query AS VARCHAR(8000)
SELECT @cols = STUFF((SELECT ',' + QUOTENAME(Name)
FROM (SELECT DISTINCT Name
FROM #test
)sub
ORDER BY Name
FOR XML PATH(''), TYPE).value('.', 'VARCHAR(MAX)')
,1,1,'')
PRINT @cols
SET @query = '
WITH cte AS (SELECT DISTINCT *
FROM #test)
,cte2 AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY Name ORDER BY Apt)RowRank
FROM cte)
SELECT *
FROM cte2
PIVOT (max(Apt) for Name in ('+@cols+')) p
'
EXEC (@query)
SQL Fiddle - Distinct List, Specific Order
编辑:如果您不希望列表不同,请消除上面的第一个 cte,如果您想保持任意顺序,请将 ORDER BY
更改为 (SELECT 1)
:
DECLARE @cols AS VARCHAR(1000),
@query AS VARCHAR(8000)
SELECT @cols = STUFF((SELECT ',' + QUOTENAME(Name)
FROM (SELECT DISTINCT Name
FROM #test
)sub
ORDER BY Name
FOR XML PATH(''), TYPE).value('.', 'VARCHAR(MAX)')
,1,1,'')
PRINT @cols
SET @query = '
WITH cte AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY Name ORDER BY (SELECT 1))RowRank
FROM #test)
SELECT *
FROM cte
PIVOT (max(Apt) for Name in ('+@cols+')) p
'
EXEC (@query)
SQL Fiddle - Full List, Arbitrary Order
最后,如果您不想在结果中包含 RowRank
字段,只需在 SELECT
中重复使用 @cols
变量即可>:
SET @query = '
WITH cte AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY Name ORDER BY (SELECT 1))RowRank
FROM #test)
SELECT '+@cols+'
FROM cte
PIVOT (max(Apt) for Name in ('+@cols+')) p
'
EXEC (@query)
关于sql - 分组和切换列和行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18282758/