.net - 给出一个数字以返回 Enum 的近似值？

Question

我有这个枚举:

Enum Lame_Bitrate
    kbps_8 = 8
    kbps_16 = 16
    kbps_24 = 24
    kbps_32 = 32
    kbps_40 = 40
    kbps_48 = 48
    kbps_56 = 56
    kbps_64 = 64
    kbps_80 = 80
    kbps_96 = 96
    kbps_112 = 112
    kbps_128 = 128
    kbps_144 = 144
    kbps_160 = 160
    kbps_192 = 192
    kbps_224 = 224
    kbps_256 = 256
    kbps_320 = 320
End Enum

我想返回给定数字的枚举的近似值。

例如，如果我有数字190，那么我希望在枚举中找到更近似的值以返回192(枚举的kbps_192值)，如果我有数字196，那么我再次期望返回值192(不返回下一个值224，因为不太近似)。

类似这样的事情:

Private Sub Test()

    Dim wma_file As String = "C:\windows media audio file.wma"
    Dim wma_file_Bitrate As Integer = 172
    Dim mp3_bitrate_approximated As Integer

    mp3_bitrate_approximated = Return_Approximated_Value_Of_Enum(wma_file_Bitrate)

End Sub

private function Return_Approximated_Value_Of_Enum(byval value as integer) as integer

    return... enum.find(value).approximated...

end function

是否存在任何框架方法来查找枚举中给定其他数字的更近似数字？

希望您能理解我的问题，谢谢。

PS:如果可以的话，我更喜欢使用 LINQ 扩展的解决方案。

Answer 1

如果你想找到最近的枚举:

Dim number = 190
Dim allBitrates() As Lame_Bitrate = DirectCast([Enum].GetValues(GetType(Lame_Bitrate)), Lame_Bitrate())
Dim nearestBitrate = allBitrates.OrderBy(Function(br) Math.Abs(number - br)).First()

如果您想查找所有最近的枚举(如果有多个具有相同最小距离的枚举):

number = 120 ' two with the same distance
Dim nearestBitrates As IEnumerable(Of Lame_Bitrate) = allBitrates.
    GroupBy(Function(br) Math.Abs(number - br)).
    OrderBy(Function(grp) grp.Key).
    First()
Console.Write(String.Join(",", nearestBitrates))

输出:

kbps_112,kbps_128