php - Silex框架: Create an UserProvider/PasswordEncoder/User

Question

我使用Silex框架，特别是SecurityServiceProvider。

我必须创建自己的 User 类(因为我的盐是用户名 => 默认类盐为 null):

<?php
namespace Adh\Security;

use Symfony\Component\Security\Core\User\AdvancedUserInterface;

class User implements AdvancedUserInterface {

  private $username;
  private $password;

  public function __construct($username, $password)
  {
    $this->username = $username;
    $this->password = $password;
  }

  public function getRoles()
  {
    return array();
  }

  public function getPassword()
  {
    return $this->password;
  }

  public function getSalt()
  {
    return $this->username;
  }
...
}

到目前为止，没有问题。现在，我必须创建一个自定义 UserProvider 来从 MySQL 检索我的用户:

<?php
namespace Adh\Security;

use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\User;
use Symfony\Component\Security\Core\Exception\UnsupportedUserException;
use Symfony\Component\Security\Core\Exception\UsernameNotFoundException;
use Doctrine\DBAL\Connection;

class UserProvider implements UserProviderInterface
{
  private $conn;

  public function __construct(Connection $conn)
  {
    $this->conn = $conn;
  }

  public function loadUserByUsername($username)
  {
    $stmt = $this->conn->executeQuery('SELECT * FROM account WHERE username like ?', array($username));

    if (!$user = $stmt->fetch()) {
      throw new UsernameNotFoundException(sprintf('Le nom d\'utilisateur "%s" n\'existe pas', $username));
    }

    return new \Adh\Security\User($user['username'], $user['sha_pass_hash']);
  }
  ...
}

并注册安全提供程序:

$app->register(new Silex\Provider\SecurityServiceProvider(), array(
  'security.firewalls' => array(
    'user' => array(
      'pattern' => '^/user',
      'form' => array('login_path' => '/connexion', 'check_path' => '/user'),
      'users' => $app->share(function () use ($app) {
        return new Adh\Security\UserProvider($app['db']);
      })
    )
  )
));

$app['security.encoder_factory'] = $app->share(function ($app) {
  return new EncoderFactory(
    array('Adh\Security\User' => new Adh\Security\PasswordEncoder())
    );
});

它有效，除非身份验证是肯定的(用户名和密码匹配)我有这个异常(exception):

RuntimeException: There is no user provider for user "Adh\Security\User".

如何为我的 User 类设置 UserProvider ？

谢谢

Answer 1

我找到了解决方案。为了创建我的提供程序，我遵循了以下示例:http://silex.sensiolabs.org/doc/providers/security.html#defining-a-custom-user-provider

在refreshUser方法中:

if (!$user instanceof User) {
   throw new UnsupportedUserException(sprintf('Instances of "%s" are not supported.', get_class($user)));
}

这对于默认的 User 类是正确的:我有自己的 User 类，因此会引发异常。

条件变为:

if (!$user instanceof \Adh\Security\User) {
   throw new UnsupportedUserException(sprintf('Instances of "%s" are not supported.', get_class($user)));
}