我需要在 R 中采用一种优雅的方式来获取 urlencoded 字符串，例如:
test.aspx?title=Pancreas%20Cancer&startYear=2000&dataCSV=461%2C520%2C559%2C627%2C1065%2C1217%2C1323%2C1512%2C2160%2C2554%2C2707%2C3000%2C3495%2C4163%2C4927%2C5237%2C4785%2C5559%2C6490%2C7559%2C5106%2C6358%2C6824%2C7980%2C4873%2C6715%2C7038%2C8156%2C4863%2C6460%2C7244%2C9161%2C5237%2C6176%2C6531%2C9068%2C5628%2C5983%2C5871%2C7951%2C6060%2C6089%2C5520%2C6627%2C5722%2C6099%2C5586%2C5822%2C4185%2C4909%2C5053%2C5273%2C5227%2C6077%2C6681%2C7977%2C
并获取一个列表，该列表使用 URL 中发送的键和发送的值:
list ( title = "Pancreas Cancer",
startYear = 2000,
dataCSV = matrix ( c(461, 520....etc), nrows = X, byrow = TRUE)
);
在 R 中是否可以轻松地做到这一点？
最佳答案
httr提供了解析url的函数，这是一个例子:
url <- "test.aspx?title=Pancreas%20Cancer&startYear=2000&dataCSV=461%2C520%2C559%2C627%2C1065%2C1217%2C1323%2C1512%2C2160%2C2554%2C2707%2C3000%2C3495%2C4163%2C4927%2C5237%2C4785%2C5559%2C6490%2C7559%2C5106%2C6358%2C6824%2C7980%2C4873%2C6715%2C7038%2C8156%2C4863%2C6460%2C7244%2C9161%2C5237%2C6176%2C6531%2C9068%2C5628%2C5983%2C5871%2C7951%2C6060%2C6089%2C5520%2C6627%2C5722%2C6099%2C5586%2C5822%2C4185%2C4909%2C5053%2C5273%2C5227%2C6077%2C6681%2C7977%2C"
library(httr)
str(parse_url(url)$query)
关于r - 将 R 中 URL 编码的 GET 字符串解析为列表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20505022/