我有一张包含以下详细信息的表格
Repid | buildDate | BuildVersion
---------------------------------
1 2013-11-15 10:41:00 1683
1 2013-11-15 11:10:00 1684
1 2013-11-15 12:14:00 1685
2 2013-11-15 10:41:00 1688
2 2013-11-15 11:10:00 1689
2 2013-11-15 12:14:00 1690
对于每个Repid,我需要找到连续构建版本之间的平均小时差异。
最佳答案
select b1.RepId
, avg(abs(datediff(hour, b1.buildDate, b2.buildDate)))
from builds b1
join builds b2
on b1.BuildVersion = b2.BuildVersion + 1
and b1.Repid = b2.Repid
group by
b1.RepId
关于sql - 查找日期之间差异的平均值 -Sql Select,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20610523/