sql - 在 Sql Server 查询中忽略分组依据中的日期列

Question

我想从表中选择日期列值，但不想按日期分组。 是否可以。 因为我想使用其他列对数据进行分组。

SELECT DISTINCT gin.GoodsIssueNoteNumber,gini.GoodsIssueNoteItemNumber, 
                sp.OrgPath,ISNULL(gini.IssuedQuantity,0) as 'Quantity', 
                gin.MRN, sp.SpareName,sp.SysId as 'spareid',
                stc.StoreName,sp.ItemGroupName,sp.PartCode,
                SUM(stc.StockCount) as stockCount,
                SUM(stc.TotalInventoryValue) as StockValue,
                ISNULL(gini.Cost,0) as WeightedAverageItemCost,
                ROUND (gini.IssuedQuantity * gini.Cost,2) as 'TotalIssued Cost',
                gin.Date as 'GIDATE'
FROM vwSpare sp         
INNER JOIN vwGoodsIssueNoteItem gini 
  on sp.SysId=gini.Spare 
INNER JOIN vwGoodsIssueNote gin 
  on gin.SysId in (SELECT AssociatingId FROM GoodsIssueNoteAssociation 
                   WHERE AssociatedId=gini.SysId and IsActive=1)    
LEFT JOIN vwStock stc 
  on stc.Spare=sp.SysId and stc.GoodsIssueNoteId is not null 
 and gin.StoreIDName=stc.StoreName
WHERE IsRepairable=0 and Scrap=0 and Repaired=0 and sp.IsActive=1  
  and gin.IsActive=1 and gin.Date > DATEADD(mm,-6,GETDATE()) and gini.IsActive=1 
GROUP BY sp.SpareName,stc.StoreName,sp.OrgPath,gini.IssuedQuantity,gin.MRN,
         sp.SysId,sp.ItemGroupName,sp.PartCode,gini.Cost,
         gin.GoodsIssueNoteNumber,gini.GoodsIssueNoteItemNumber,gin.Date

我不需要 gin.Date in group by

Answer 1

SQL 要求所有非聚合字段都位于 GROUP BY 子句中。但是，您可以这样做:

SELECT b.ungroupedColumn,  -- your ungrouped columns
       a.* -- your grouped columns
FROM (SELECT Column1, Column2, sum(Column3)
      FROM mytable
      GROUP BY Column1, Column2) a
INNER JOIN mytable b ON a.Column1 = b.Column1

我们的想法是，您带回分组数据，减去额外的列，然后将这些结果连接回表中以添加未分组的列。

这是一个示例，假设我有以下产品库存:

Type       Name       Qty
---------- ---------- -----------
Fruit      Apple      1
Fruit      Orange     2
Fruit      Banana     3
Vegetable  Carrot     4
Vegetable  Cucumber   5
Vegetable  Peas       6

我可以运行以下查询:

SELECT b.[Name],
       a.*
FROM (SELECT [Type], sum ([Qty]) as Qty_Of_Type
      FROM Produce
      GROUP BY [Type]) a
INNER JOIN Produce b ON a.[Type] = b.[Type]

它将返回以下结果:

Name       Type       Qty_Of_Type
---------- ---------- -----------
Apple      Fruit      6
Orange     Fruit      6
Banana     Fruit      6
Carrot     Vegetable  15
Cucumber   Vegetable  15
Peas       Vegetable  15