我正在研究几个 C++11 工作队列类。第一类,command_queue 是一个多生产者单消费者工作队列。多个线程可以发布命令,单个线程循环调用“wait()”和“pop_back()”来处理这些命令。
第二个类,Actor 使用 command_queue 并实际上提供了一个消费者线程...除此之外,其想法是 post() 将返回一个 future,以便客户端可以阻塞直到命令被处理,或者继续运行(actor还添加了结果类型的想法)。为了实现这一点,我尝试将 std::promise 存储在工作队列中的 std::pair 中。我相信我已经相当接近了,但是我在下面的 _entry_point 函数中遇到了问题......具体来说,当我试图将 std::pair 从命令队列中取出时,我得到了“使用已删除function”编译器错误...我将从编译器得到的实际错误放在代码下方(您应该能够将其保存到文本文件并自己编译,它是独立的 c++11 代码) .
#include <mutex>
#include <condition_variable>
#include <future>
#include <list>
#include <stdio.h>
template<class T>
class command_queue
{
public:
command_queue() = default;
command_queue( const command_queue& ) = delete;
virtual ~command_queue() noexcept = default;
command_queue& operator = ( const command_queue& ) = delete;
void start()
{
std::unique_lock<std::recursive_mutex> g( _queueLock );
_started = true;
}
bool started()
{
return _started;
}
void stop()
{
std::unique_lock<std::recursive_mutex> g( _queueLock );
_started = false;
_queueCond.notify_one();
}
void post_front( const T& cmd )
{
std::unique_lock<std::recursive_mutex> g( _queueLock );
_queue.push_front( cmd );
_queueCond.notify_one();
}
void post_front( T&& cmd )
{
std::unique_lock<std::recursive_mutex> g( _queueLock );
_queue.push_front( cmd );
_queueCond.notify_one();
}
void wait()
{
std::unique_lock<std::recursive_mutex> g( _queueLock );
_queueCond.wait( g, [this](){return !this->_queue.empty() ? true : !this->_started;});
}
T pop_back()
{
std::unique_lock<std::recursive_mutex> g( _queueLock );
auto val = _queue.back();
_queue.pop_back();
return val;
}
private:
std::recursive_mutex _queueLock;
std::condition_variable_any _queueCond;
std::list<T> _queue;
bool _started = false;
};
template<class T, class U>
class actor
{
public:
actor() :
_started( false ),
_thread(),
_queue()
{
}
actor( const actor& ) = delete;
virtual ~actor() noexcept
{
if( _started )
stop();
}
actor& operator = ( const actor& ) = delete;
void start()
{
_started = true;
_queue.start();
_thread = std::thread( &actor<T,U>::_entry_point, this );
}
void stop()
{
_started = false;
_queue.stop();
_thread.join();
}
std::future<U> post( const T& cmd )
{
std::promise<U> p;
std::future<U> waiter = p.get_future();
_queue.post_front( std::pair<T,std::promise<U>>(cmd, std::move(p)) );
return waiter;
}
virtual U process( const T& cmd ) = 0;
protected:
void _entry_point()
{
while( _started )
{
_queue.wait();
if( !_started )
continue;
std::pair<T,std::promise<U>> item = _queue.pop_back();
item.second.set_value( process( item.first ) );
}
}
bool _started;
std::thread _thread;
command_queue<std::pair<T,std::promise<U>>> _queue;
};
class int_printer : public actor<int,bool>
{
public:
virtual bool process( const int& cmd ) override
{
printf("%d",cmd);
return true;
}
};
using namespace std;
int main( int argc, char* argv[] )
{
// std::promise<bool> p;
// list<std::pair<int,std::promise<bool>>> promises;
// promises.push_back( make_pair<int,std::promise<bool>>(10,std::move(p)) );
int_printer a;
a.start();
future<bool> result = a.post( 10 );
a.stop();
}
[developer@0800275b874e projects]$ g++ -std=c++11 pf.cpp -opf -lpthread
pf.cpp: In instantiation of ‘T command_queue<T>::pop_back() [with T = std::pair<int, std::promise<bool> >]’:
pf.cpp:133:65: required from ‘void actor<T, U>::_entry_point() [with T = int; U = bool]’
pf.cpp:99:9: required from ‘void actor<T, U>::start() [with T = int; U = bool]’
pf.cpp:163:13: required from here
pf.cpp:60:32: error: use of deleted function ‘constexpr std::pair<_T1, _T2>::pair(const std::pair<_T1, _T2>&) [with _T1 = int; _T2 = std::promise<bool>]’
In file included from /usr/lib/gcc/x86_64-redhat-linux/4.7.0/../../../../include/c++/4.7.0/utility:72:0,
from /usr/lib/gcc/x86_64-redhat-linux/4.7.0/../../../../include/c++/4.7.0/tuple:38,
from /usr/lib/gcc/x86_64-redhat-linux/4.7.0/../../../../include/c++/4.7.0/mutex:39,
from pf.cpp:2:
/usr/lib/gcc/x86_64-redhat-linux/4.7.0/../../../../include/c++/4.7.0/bits/stl_pair.h:119:17: note: ‘constexpr std::pair<_T1, _T2>::pair(const std::pair<_T1, _T2>&) [with _T1 = int; _T2 = std::promise<bool>]’ is implicitly deleted because the default definition would be ill-formed:
/usr/lib/gcc/x86_64-redhat-linux/4.7.0/../../../../include/c++/4.7.0/bits/stl_pair.h:119:17: error: use of deleted function ‘std::promise<_Res>::promise(const std::promise<_Res>&) [with _Res = bool]’
In file included from pf.cpp:4:0:
/usr/lib/gcc/x86_64-redhat-linux/4.7.0/../../../../include/c++/4.7.0/future:963:7: error: declared here
In file included from /usr/lib/gcc/x86_64-redhat-linux/4.7.0/../../../../include/c++/4.7.0/list:64:0,
from pf.cpp:5:
最佳答案
Promise 是不可复制的(这是有道理的 - 它们代表了一种独特的状态)。您需要在多个地方使用 std::move
来转移 Promise 的唯一所有权。
具体来说,您的自制队列类需要允许移动,例如
auto val = std::move(_queue.back());
_queue.pop_back();
return val;
关于c++11 - 将 std::promise 对象存储在 std::pair 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21500381/