scala - 如何在scala中获取reflect.runtime.universe.Type的类型参数？

Question

假设我得到一个代表 List[Int] 的类型:

> import scala.reflect.runtime.universe
> val mirror = universe.runtimeMirror(this.getClass.getClassLoader)
mirror: reflect.runtime.universe.Mirror = JavaMirror with ...

> class X{ def getList():List[Int] = null  }
defined class X

> val method = mirror.
    classSymbol(classOf[X]).
    toType.
    declarations.
    filter{_.isMethod}.
    map{_.asInstanceOf[universe.MethodSymbol]}.
    filter{ m => m.
    name.
    toString()=="getList" }.
    head   
method: reflect.runtime.universe.MethodSymbol = method getList

> val rt = method.returnType
rt: reflect.runtime.universe.Type = scala.List[scala.Int]

如何从reflect.runtime.universe.Type(显然知道类型参数scala.Int)到实际类型参数？

我看到 TypeSymbol 有一个参数

一些实验..

rt.typeSymbol  // reflect.runtime.universe.Symbol = class List ... Int is erased
rt.typeSymbol.asInstanceOf[TypeSymbol].typeParams // List[reflect.runtime.universe.Symbol] = List(type A)
rt.takesTypeArgs  // false !!
rt.termSymbol  //None
rt.typeSymbol.typeSignature // Much, talk about generics, but no Int
rt.typeSymbol.asInstanceOf[TypeSymbol].typeParams  // List[reflect.runtime.universe.Symbol] = List(type A)
rt.getClass  // Class[_ <: reflect.runtime.universe.Type] = class scala.reflect.internal.Types$TypeRef$$anon$1
rt.asInstanceOf[TypeRef].sym  // List

Answer 1

斯卡拉2.11

您需要rt.typeArgs，它返回类型列表(在您的情况下，它包含单个元素:Int)。

斯卡拉2.10

val args = returnType match {
  case r: universe.TypeRefApi => r.args
  case _ => List()
}