我有以下数据:
================================================================
session_id screen_name screen_launch_time
================================================================
990004916946605-1404157897784 screen1 1404157898275
990004916946605-1404157897784 screen2 1404157898337
990004947764274-1435162269418 screen1 1435162274044
990004947764274-1435162269418 screen3 1435162274081
我想使用 array_agg
函数来获取以下格式的数据:
=========================================================
session_id screen_flow count
=========================================================
990004916946605-1404157897784 screen1->screen2 1
990004947764274-1435162269418 screen1->screen3 1
有人尝试过编写 UDAF
或 python
脚本来实现 array_agg
函数中使用的逻辑吗?
请分享您的想法。
最佳答案
只需按 session_id
进行分组,连接 screen_name
,然后计算每组的记录数。如果您不想构建 brickhouse jar 中,您可以使用 collect_list()
而不是 collect()
(但我不推荐它)。
查询:
add jar /path/to/jars/brickhouse-0.7.1.jar;
create temporary function collect as "brickhouse.udf.collect.CollectUDAF";
select session_id, screen_flow
, count(*) count
from (
select session_id
, concat_ws('->', collect(screen_name)) screen_flow
from db.table
group by session_id ) x
group by session_id, screen_flow
输出:
990004916946605-1404157897784 screen1->screen2 1
990004947764274-1435162269418 screen1->screen3 1
关于python - 如何在pig或hive中使用array_agg()聚合函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32654691/