php - 如何使用php在json文件中查找数据

Question

使用 PHP，我希望获取通过 url 传递的 id，然后在 JSON 文件中查找一些数据...然后将数据显示回页面上。

我将把 url 设置为 http://mytestapp.php?id=12345678 然后使用；

$id = $_GET['id']; 

设置 id 变量。然后我有一个如下的 JSON；

{
    "ads": 
    [
        {   "id":"12345678", 
            "hirername":"Test Hirer", 
            "hirercontact":"Rob A",
            "role":"Ultra Sat Role",
            "requirements": [
                {"req":"Right to work in Australia"},
                {"req":"Live locally"}],
            "candidates": [
                {"name":"John Smith","dist":"Nunawading (23km away)","exp1":"Pizza maker at Don Domenicos for 4 years","exp2":"Bakery Assistant at Woolworths for 4 years","req":"","avail1":"Mon to Fri | Morning, Evening & Night","avail2":"","call":"0413451007"},
                {"name":"Jack Smith","dist":"Endeadvour Hills (35km away)","exp1":"Pizzaiolo (Pizza maker) at Cuor Di Pizza for 1 year","exp2":"","req":"","avail1":"Mon to Fri | Morning & Evening","avail2":"","call":"041345690"}]
        }, 

        {   "id":"12345679", 
            "hirername":"Test Hirer 2", 
            "hirercontact":"Jesse S",
            "role":"Ultra Sat Role 2",
            "requirements": [
                {"req":"Right to work in Australia"},
                {"req":"Live locally"}],
            "candidates": [
                {"name":"Jill Smith","dist":"Nunawading (23km away)","exp1":"Pizza maker at Don Domenicos for 4 years","exp2":"Bakery Assistant at Woolworths for 4 years","req":"","avail1":"Mon to Fri | Morning, Evening & Night","avail2":"","call":"0413451007"},
                {"name":"Jenny Smith","dist":"Endeadvour Hills (35km away)","exp1":"Pizzaiolo (Pizza maker) at Cuor Di Pizza for 1 year","exp2":"","req":"","avail1":"Mon to Fri | Morning & Evening","avail2":"","call":"041345690"}]
        }

    ]
}   

我想搜索id，然后能够将数据内容回显出来。

我正在读取 JSON 并解码为数组；

    $json = file_get_contents('data.json');
    $arr = json_decode($json, true);

但是我现在不知道如何读取数组，根据id找到我想要的数据，然后拉出数据，以便我可以将其显示在页面上，如下；

Hirer: Test Hirer

Contact: Rob A 

Role: Ultra Sat Role



Requirements: 

- Right to work in Australia

- Live Locally



John Smith Nunawading (23km away) 

Pizza maker at Don Domenicos for 4 years 

Bakery Assistant at Woolworths for 4 years 

Mon to Fri | Morning, Evening & Night 

0413451007



Jack Smith Endeadvour Hills (35km away) 

Pizzaiolo (Pizza maker) at Cuor Di Pizza for 1 year 

Mon to Fri | Morning & Evening 

041345690

有什么想法吗？

谢谢罗布。

Answer 1

借用@RobbieAverill 的示例并进行修改以满足您的需求，请检查这是否有效。

<?php
    $id = $_GET['id']; 

    $json = file_get_contents('data.json');

    $foundAd = null;
    $json = json_decode($json,true);
    foreach ($json['ads'] as $ad) {
        if ($ad['id'] == $id) {
            $foundAd = $ad;
            break;
        }
    }

    echo "Hirer:".$foundAd['hirername']."<br/>";
    echo "contact:".$foundAd['hirercontact']."<br/>";
    echo "role:".$foundAd['role']."<br/><br/>";

    echo "Requirements<br/>";

    echo "<ul>";
    foreach($foundAd['requirements'] as $req){
        echo "<li>".$req['req']."</li>";            
    }
    echo "</ul><br/>";

    foreach($foundAd['candidates'] as $req){
        echo $req['name']." ". $req['dist']."</br>";
        echo $req['exp1']."</br>";
        echo $req['exp1']."</br>";
        echo $req['avail1']."</br>";
        if($req['avail2']!=""){
            echo $req['avail2']."</br>";;       
        }
        echo $req['call']."</br></br>";
    }

?>