curl - 如何编写具有命名多部分主体的 curl

Question

我有一个接受多部分文件的资源，它看起来像这样:

@FormDataParam("file") InputStream inputStream

我想向该资源写入curl，但我不知道如何将此参数命名为"file"。

你有什么想法吗？

Answer 1

使用-F切换到多部分发送。当您至少使用此开关时，Content-Type 将自动设置为 multipart/form-data。您可以拥有多个。对于每一个，您可以设置值 <name>=<value> 。 <value>可以是一个文件，使用 @在值前面。例如-F "file=@path_to_file" 。来自the manpage

-F, --form <name=content>

(HTTP) This lets curl emulate a filled-in form in which a user has pressed the submit button. This causes curl to POST data using the Content-Type multipart/form-data according to RFC 2388. This enables uploading of binary files etc. To force the 'content' part to be a file, prefix the file name with an @ sign. To just get the content part from a file, prefix the file name with the symbol <. The difference between @ and < is then that @ makes a file get attached in the post as a file upload, while the < makes a text field and just get the contents for that text field from a file.

Example: to send an image to a server, where 'profile' is the name of the form-field to which portrait.jpg will be the input:

curl -F <a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="2d5d5f424b444148106d5d425f595f4c445903475d4a" rel="noreferrer noopener nofollow">[email protected]</a> https://example.com/upload.cgi

To read content from stdin instead of a file, use - as the filename. This goes for both @ and < constructs. Unfortunately it does not support reading the file from a named pipe or similar, as it needs the full size before the transfer starts.

You can also tell curl what Content-Type to use by using 'type=', in a manner similar to:

curl -F "<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="88ffedeab5c8e1e6ecedf0a6e0fce5e4" rel="noreferrer noopener nofollow">[email protected]</a>;type=text/html" example.com

or

curl -F "name=daniel;type=text/foo" example.com

You can also explicitly change the name field of a file upload part by setting filename=, like this:

curl -F "file=@localfile;filename=nameinpost" example.com

If filename/path contains ',' or ';', it must be quoted by double-quotes like:

curl -F "file=@\"localfile\";filename=\"nameinpost\"" example.com

or

curl -F 'file=@"localfile";filename="nameinpost"' example.com

Note that if a filename/path is quoted by double-quotes, any double-quote or backslash within the filename must be escaped by backslash.

See further examples and details in the MANUAL.

This option can be used multiple times.