标题几乎说明了一切:在 C++ 中有没有一种方法可以在编译时获取类的基类型? IE。是否可以将一个类传递给一个模板,然后让该模板使用它传递给定类的基类的其他模板?
我的问题不是我是否可以自己实现这样的功能,毫无疑问我可以(使用特征等)。我的问题是是否有一些(晦涩的)内置功能可用于此目的。
最佳答案
gcc
支持这一点。见
- Kerrek's answer
- tr2/type_traits
- Andy Prowl's code example
- n2965
- What is the status of N2965 - std::bases and std::direct_bases?
- How to query for all base classes of a class at compile time?
n2965 提供了一个例子。
This simple examples illustrates the results of these type traits. In the Suppose we have the following class hierarchy:
class E {}; class D {}; class C : virtual public D, private E {}; class B : virtual public D, public E {}; class A : public B, public C {};
It follows that
bases<A>::type is tuple<D, B, E, C, E>
Similarly,
direct_bases<A>::type is tuple<B, C>
Andy Prowl的代码示例如下:
#include <tr2/type_traits>
#include <tuple>
template<typename T>
struct dbc_as_tuple { };
template<typename... Ts>
struct dbc_as_tuple<std::tr2::__reflection_typelist<Ts...>>
{
typedef std::tuple<Ts...> type;
};
struct A {};
struct B {};
struct C : A, B {};
int main()
{
using namespace std;
using direct_base_classes = dbc_as_tuple<tr2::direct_bases<C>::type>::type;
using first = tuple_element<0, direct_base_classes>::type;
using second = tuple_element<1, direct_base_classes>::type;
static_assert(is_same<first, A>::value, "Error!"); // Will not fire
static_assert(is_same<second, B>::value, "Error!"); // Will not fire
}
关于c++ - 在编译时查找基类,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20798707/