python - 如何使用 Cython 公开将 C++ 对象返回给 Python 的函数?

标签 python c++ cython

我正在使用 Cython 构建 C++<->Python 绑定(bind),但我找不到如何从 Python 方法返回 C++ 对象。

更具体地说,在编译 peak_detection_.pyx 时,如下所示,我得到

peak_detection_.pyx:35:36: Cannot convert 'vector[Peak]' to Python object

最后几行

def getPeaks(self,data):
    return self.thisptr.getPeaks(data)

我理解这个错误,但我不介意一些关于如何修复它的帮助/指示。

peak_detection.hpp

#ifndef PEAKDETECTION_H
#define PEAKDETECTION_H

#include <string>
#include <map>
#include <vector>

#include "peak.hpp"


class PeakDetection
{
    public:
        PeakDetection(std::map<std::string, std::string> config);
        std::vector<Peak> getPeaks(std::vector<float> &data);

    private:
        float _threshold;               
};

#endif

peak_detection.cpp

#include <iostream>
#include <string>

#include "peak.hpp"
#include "peak_detection.hpp"


using namespace std;


PeakDetection::PeakDetection(map<string, string> config)
{   
    _threshold = stof(config["_threshold"]);
}

vector<Peak> PeakDetection::getPeaks(vector<float> &data){

    Peak peak1 = Peak(10,1);
    Peak peak2 = Peak(20,2);

    vector<Peak> test;
    test.push_back(peak1);
    test.push_back(peak2);

    return test;
}

峰值.hpp

#ifndef PEAK_H
#define PEAK_H

class Peak {
    public:
        float freq;
        float mag;

        Peak() : freq(), mag() {}
        Peak(float f, float m) : freq(f), mag(m) {}
};

#endif

peak_detection_.pyx

# distutils: language = c++
# distutils: sources = peak_detection.cpp

from libcpp.vector cimport vector
from libcpp.map cimport map
from libcpp.string cimport string

cdef extern from "peak.hpp":
    cdef cppclass Peak:
        Peak()

cdef class PyPeak:
    cdef Peak *thisptr
    def __cinit__(self):
        self.thisptr = new Peak()
    def __dealloc__(self):
        del self.thisptr

cdef extern from "peak_detection.hpp":
    cdef cppclass PeakDetection:
        PeakDetection(map[string,string])
        vector[Peak] getPeaks(vector[float])

cdef class PyPeakDetection:
    cdef PeakDetection *thisptr
    def __cinit__(self, map[string,string] config):
        self.thisptr = new PeakDetection(config)
    def __dealloc__(self):
        del self.thisptr
    def getPeaks(self, data):
        return self.thisptr.getPeaks(data)

最佳答案

这里的问题是 cython 不知道如何自动将 C++ 对象 Peak 转换为 python 包装版本 PyPeak

getPeaks 返回的 Peak 实例复制到 PyPeak 实例列表中的版本是:

# distutils: language = c++
# distutils: sources = peak_detection.cpp

from libcpp.vector cimport vector
from libcpp.map cimport map
from libcpp.string cimport string

cdef extern from "peak.hpp":
    cdef cppclass Peak:
        Peak()
        Peak(Peak &)
        float freq, mag


cdef class PyPeak:
    cdef Peak *thisptr

    def __cinit__(self):
        self.thisptr = new Peak()

    def __dealloc__(self):
        del self.thisptr

    cdef copy(self, Peak &other):
        del self.thisptr
        self.thisptr = new Peak(other)

    def __repr__(self):
        return "<Peak: freq={0}, mag={1}>".format(self.freq, self.mag)

    property freq:
        def __get__(self): return self.thisptr.freq
        def __set__(self, freq): self.thisptr.freq = freq

    property mag:
        def __get__(self): return self.thisptr.mag
        def __set__(self, mag): self.thisptr.mag = mag


cdef extern from "peak_detection.hpp":
    cdef cppclass PeakDetection:
        PeakDetection(map[string,string])
        vector[Peak] getPeaks(vector[float])

cdef class PyPeakDetection:
    cdef PeakDetection *thisptr

    def __cinit__(self, map[string,string] config):
        self.thisptr = new PeakDetection(config)

    def __dealloc__(self):
        del self.thisptr

    def getPeaks(self, data):
        cdef Peak peak
        cdef PyPeak new_peak
        cdef vector[Peak] peaks = self.thisptr.getPeaks(data)

        retval = []

        for peak in peaks:
            new_peak = PyPeak()
            new_peak.copy(peak)
            retval.append(new_peak)

        return retval

编译并运行后,我们得到了预期的输出:

In [1]: import peak_detection_

In [2]: print peak_detection_.PyPeakDetection({"_threshold" : "0.01"}).getPeaks([1,2,3])
[<Peak: freq=10.0, mag=1.0>, <Peak: freq=20.0, mag=2.0>]

关于python - 如何使用 Cython 公开将 C++ 对象返回给 Python 的函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33573038/

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