我有一个看起来像这样的数据框:
var1 var2
1 927720_2005 927720_2006
2 927720_2006 927720_2007
3 841555_2005 841555_2006
4 88095_2005 88095_2006
5 1003464_2005 1003464_2006
6 1003464_2005 1003464_2006
7 1003464_2006 1003464_2007
8 1037388_2005 1037388_2006
9 1037388_2006 1037388_2007
观察1003464_2005
在专栏 var1
是重复的,所以当我申请 rownames(MyMatrix) <- df$var1
时rownames 有一个观察结果为 1003464_2005
另一个为 1003464_2005.1
。我不介意这一点,但当我使用 colnames(MyMatrix) <- df$var2
时,列名允许有重复项。 .
我想让数据:
var1 var2
1 927720_2005 927720_2006
2 927720_2006 927720_2007
3 841555_2005 841555_2006
4 88095_2005 88095_2006
5 1003464_2005 1003464_2006
6 1003464_2005.1 1003464_2006.1
7 1003464_2006 1003464_2007
8 1037388_2005 1037388_2006
9 1037388_2006 1037388_2007
如果我在var1
中有“3个重复项”只需在 1003464_2005.2
上添加另一个“计数器”即可或1003464_2005.1.1
。这样我在 var1
中就不会出现重复项。列以及已“添加”到 var1
的内容列添加到 var2
专栏。
预先感谢您的帮助!
数据:
df <- structure(list(var1 = structure(c(7L, 8L, 5L, 6L, 1L, 1L, 2L,
3L, 4L), .Label = c("1003464_2005", "1003464_2006", "1037388_2005",
"1037388_2006", "841555_2005", "88095_2005", "927720_2005", "927720_2006"
), class = "factor"), var2 = c("927720_2006", "927720_2007",
"841555_2006", "88095_2006", "1003464_2006", "1003464_2006",
"1003464_2007", "1037388_2006", "1037388_2007")), class = "data.frame", row.names = c(NA,
-9L))
对于重复的行名,我的矩阵如下所示:
structure(c(0.0000000000000000111365086910415, 0.0242390433922595,
0.294121286748089, 0.302965878225595, 0.259626633772708, 0.25760904856241,
0.248574305825551, 0.17848782814175, 0.191657814393258, 0.0242390433922595,
0.0000000000000000113968217215608, 0.310381807852827, 0.293653514681392,
0.245957439956465, 0.249142123526167, 0.251115609138352, 0.166302748882678,
0.176256028117321, 0.294121286748089, 0.310381807852827, -0.00000000000000000151197688178523,
0.355703128500295, 0.319662657194485, 0.317127296846476, 0.305644319511071,
0.255031411391534, 0.275597914790561, 0.302965878225595, 0.293653514681392,
0.355703128500295, 0.00000000000000000801369440490437, 0.309841957462355,
0.311910981514099, 0.317253692884325, 0.254335300246398, 0.265496031285385,
0.259626633772708, 0.245957439956465, 0.319662657194485, 0.309841957462355,
0.0000000000000000105380873106143, 0.0104634838149491, 0.0245937753301301,
0.221744045353809, 0.22476375867925, 0.25760904856241, 0.249142123526167,
0.317127296846476, 0.311910981514099, 0.0104634838149491, 0.00000000000000000986038424517971,
0.0257337720292454, 0.220483645448676, 0.224712591289328, 0.248574305825551,
0.251115609138352, 0.305644319511071, 0.317253692884325, 0.0245937753301301,
0.0257337720292454, 0.0000000000000000121630774340264, 0.213285559165696,
0.229922308724439, 0.17848782814175, 0.166302748882678, 0.255031411391534,
0.254335300246398, 0.221744045353809, 0.220483645448676, 0.213285559165696,
0.0000000000000000139766402734024, 0.0152113168185518, 0.191657814393258,
0.176256028117321, 0.275597914790561, 0.265496031285385, 0.22476375867925,
0.224712591289328, 0.229922308724439, 0.0152113168185518, 0.0000000000000000120926010568502
), .Dim = c(9L, 9L), .Dimnames = list(c("927720_2005", "927720_2006",
"841555_2005", "88095_2005", "1003464_2005", "1003464_2005",
"1003464_2006", "1037388_2005", "1037388_2006"), c("927720_2005",
"927720_2006", "841555_2005", "88095_2005", "1003464_2005", "1003464_2005",
"1003464_2006", "1037388_2005", "1037388_2006")))
最佳答案
使用make.unique
可以轻松完成。循环遍历感兴趣的列,然后应用函数 make.unique
。它期望该列是字符
类。根据 ?make.unique
names - a character vector
所以,如果是factor
,则将其转换为character
df[] <- lapply(df, function(x) make.unique(as.character(x)))
在dplyr
中,这可以类似地完成,但使用mutate_if
library(dplyr)
df %>%
mutate_if(is.factor, as.character) %>%
mutate_if(is.character, make.unique)
关于r - 将字符添加到列中的重复行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57876084/