javascript - 首先通过在其他数组中包含 ID 对数组进行排序，然后按日期排序

Question

const linkedProjects = ["2", "3"];
const projects = [
  {
    id: 1,
    name: "Project 1",
    lastUpdate: 1575976301091
  },
  {
    id: 2,
    name: "Project 2",
    lastUpdate: 1575975812091
  },
  {
    id: 3,
    name: "Project 3",
    lastUpdate: 1575976378391
  },
  {
    id: 4,
    name: "Project 4",
    lastUpdate: 15753276301091
  }
];

我想要实现的目标:

我想对包含多个对象的数组项目进行排序。

首先，它应该首先按 ID 对包含在 linkedProjects 中的对象进行排序。

其次，它应该按 lastUpdate 对剩余对象进行排序。

到目前为止我做了什么:

projects.sort((a, b) => {
    const [dateA, dateB] = [
        a.lastUpdate && a.lastUpdate.getTime(),
        b.lastUpdate && b.lastUpdate.getTime()
    ];
    if (linkedProjects && linkedProjects.length > 0) {
      if (linkedProjects.includes(a.id)) {
        return -1;
      } else {
        return 1;
      }
    }
    if (dateA === dateB) {
        console.log("0a")
        return 0;
    }
    if (!dateA) {
      console.log("1b")
        return 1;
    }
    if (!dateB) {
        console.log("-1b")
        return -1;
    }
    if (dateA > dateB) {
        console.log("-1d")
        return -1;
    }
    if (dateA < dateB) {
        console.log("1")
        return 1;
    }
    return 0;
})

按lastUpdate排序可以工作并且之前已实现，但我使用linkedProjects的新实现不起作用。

结果应该是:

[
  {
    id: 2, // included in linkedProjects
    name: "Project 2",
    lastUpdate: 1575975812091
  },
  {
    id: 3, // included in linkedProjects
    name: "Project 3",
    lastUpdate: 1575976378391
  },
  {
    id: 4,
    name: "Project 4",
    lastUpdate: 15753276301091 // is newer than Project 1
  },
  {
    id: 1,
    name: "Project 1",
    lastUpdate: 1575976301091 // is older than Project 4
  }
]

Answer 1

您可以采用一个返回项目顺序或一个大数字的函数，并按此增量或上次更新的增量进行排序。

const
    linkedProjects = [2, 3],
    getOrder = ({ id }) => (linkedProjects.indexOf(id) + 1) || Number.MAX_VALUE,
    projects = [{ id: 1, name: "Project 1", lastUpdate: 1575976301091 }, { id: 2, name: "Project 2", lastUpdate: 1575975812091 }, { id: 3, name: "Project 3", lastUpdate: 1575976378391 }, { id: 4, name: "Project 4", lastUpdate: 15753276301091 }];

projects.sort((a, b) => getOrder(a) - getOrder(b) || b.lastUpdate - a.lastUpdate);

console.log(projects);

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