python - 查找字典值列表的交集

Question

我有两个具有相同键的字典，但值不同:

a = {1: [1, 2, 3, 4, 5], 2: [6, 7, 8], 3: [1, 3, 5, 7, 9]}
b = {1: [2, 3, 4, 7], 2: [6, 7], 3: [1, 3, 15, 10]}

我正在尝试在相同的键下获得交集。我想要这个输出:

{1: [2, 3, 4], 2: [6, 7], 3: [1, 3]}

我尝试使用此命令:

dict(zip(a.keys() and b.keys(), a.values() and b.values()))
output: {1: [2, 3, 4, 7], 2: [6, 7], 3: [1, 3, 15, 10]}

但是，输出如下，这是错误的:

{1: [2, 3, 4, 7], 2: [6, 7], 3: [1, 3, 15, 10]}

Answer 1

我觉得说的很清楚了。如果没有，请要求澄清。

假设，

I have two dictionaries with the same keys

a = {1: [1, 2, 3, 4, 5], 2: [6, 7, 8], 3: [1, 3, 5, 7, 9]}
b = {1: [2, 3, 4, 7], 2: [6, 7], 3: [1, 3, 15, 10]}
c = {}

for key, val in a.items():
    c[key] = []
    for i in val:
        if i in b[key]:
            c[key].append(i)

print(c)

输出为:

{1: [2, 3, 4], 2: [6, 7], 3: [1, 3]}