import pygame
pygame.init()
width = 800
height = 600
running = True
screen = pygame.display.set_mode((width, height))
def drawGrid():
for y in range (50):
for x in range (50):
pygame.draw.rect (screen , ( 0 , 0 , 255 ) , ( ( x * 20 ) , ( y * 20 ) , 20 , 20 ) , 1)
for event in pygame.event.get():
if event.type == pygame.MOUSEBUTTONUP:
pos = event.pos
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
screen.fill((0, 0, 0))
drawGrid()
pygame.display.update()
所以我基本上创建了一个网格,并且还弄清楚了如何获取用户单击屏幕的位置。我现在想做的是,使用用户单击的位置,我想找到该位置对应的按钮。一旦我找到哪个按钮对应于用户单击的位置,我想将按钮的颜色更改为其他颜色。
编辑:
import pygame
pygame.init()
width = 800
height = 600
running = True
screen = pygame.display.set_mode((width, height))
cell_size = 20
size_x = width // cell_size
size_y = height // cell_size
grid = [[False for y in range(size_y)] for x in range(size_x)]
def drawGrid():
mouse_pos = pygame.mouse.get_pos()
for y in range (size_y):
for x in range (size_x):
# rectangle and color of cell
cell_rect = pygame.Rect(x * 20, y * 20, 20, 20)
cell_color = (0, 0, 255)
# change color of button if the mouse is on the button
if cell_rect.collidepoint(mouse_pos):
cell_color = (255, 255, 255)
elif grid[x][y]:
cell_color = (0, 255, 255)
pygame.draw.rect(screen, cell_color, cell_rect, 1)
z = 0
while running and z < 2:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.MOUSEBUTTONDOWN:
cell_x, cell_y = event.pos[0] // cell_size, event.pos[1] // cell_size
grid[cell_x][cell_y] = not grid[cell_x][cell_y]
z += 1
screen.fill((0, 0, 0))
drawGrid()
pygame.display.update()
所以基本上我想要做的是我想停止单击两个矩形之后的矩形。就像如果用户已经单击了两个框(起点和终点)一样,那么每当用户单击矩形时我不想再添加更多框。我让它工作,但问题是我只有在单击两次整个窗口关闭时才让它工作。我该如何解决这个问题?
最佳答案
切勿在应用程序循环中多次获取事件 (pygame.event.get()
)。
使用pygame.mouse.get_pos()
来获取鼠标的位置。创建 pygame.Rect
具有单元格大小和我们的对象 collidepoint()
评估鼠标是否在单元格中。
def drawGrid():
# get current mouse position
mosue_pos = pygame.mouse.get_pos()
for y in range (50):
for x in range (50):
# rectangle and color of cell
cell_rect = pygame.Rect(x * 20, y * 20, 20, 20)
cell_color = (0, 0, 255)
# change color of button if the mouse is on the button
if cell_rect.collidepoint(mosue_pos):
cell_color = (255, 255, 255)
pygame.draw.rect(screen, cell_color, cell_rect, 1)
如果您想在单击时更改单元格,则必须创建状态网格:
grid = [[False for y in range(size_y)] for x in range(size_x)]
单击单元格时更改单元格的状态:
if event.type == pygame.MOUSEBUTTONDOWN:
cell_x, cell_y = event.pos[0] // cell_size, event.pos[1] // cell_size
grid[cell_x][cell_y] = not grid[cell_x][cell_y]
根据单元格的状态设置颜色:
if grid[x][y]:
cell_color = (255, 255, 255)
参见示例:
import pygame
pygame.init()
width = 800
height = 600
running = True
screen = pygame.display.set_mode((width, height))
cell_size = 20
size_x = width // cell_size
size_y = height // cell_size
grid = [[False for y in range(size_y)] for x in range(size_x)]
def drawGrid():
for y in range(size_y):
for x in range(size_x):
# rectangle and color of cell
cell_rect = pygame.Rect(x * 20, y * 20, 20, 20)
cell_color = (0, 0, 255)
# change color of button if the mouse is on the button
if grid[x][y]:
cell_color = (255, 255, 255)
pygame.draw.rect(screen, cell_color, cell_rect, 1)
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.MOUSEBUTTONDOWN:
cell_x, cell_y = event.pos[0] // cell_size, event.pos[1] // cell_size
grid[cell_x][cell_y] = not grid[cell_x][cell_y]
screen.fill((0, 0, 0))
drawGrid()
pygame.display.update()
如果您想阻止选择单元格,则在单击 2 个框后,您必须在 MOUSEBUTTONDOWN
事件中计算所选单元格的数量:
z = 0
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == pygame.MOUSEBUTTONDOWN:
if z < 2:
cell_x, cell_y = event.pos[0] // cell_size, event.pos[1] // cell_size
grid[cell_x][cell_y] = not grid[cell_x][cell_y]
z += 1 if grid[cell_x][cell_y] else -1
# [...]
关于python - 如何在pygame中找到用户输入位置上的按钮并更改其颜色?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61767256/