我有一个如下所示的数据框。感谢 SO 社区在以下方面提供的帮助
df1 = pd.DataFrame({'person_id': [11,11, 12, 13, 14],
'date_birth': ['01/01/1961','12/30/1961', '05/29/1967', '01/01/1957', '7/27/1959']})
df1 = df1.melt('person_id', value_name='dates')
df1['dates'] = pd.to_datetime(df1['dates'])
df_ranges = df1.assign(until_prev_year_days=(df1['dates'].dt.dayofyear - 1),
until_next_year_days=((df1['dates'] + pd.offsets.YearEnd(0)) - df1['dates']).dt.days)
f = {'until_prev_year_days': 'min', 'until_next_year_days': 'min'}
min_days = df_ranges.groupby('person_id',as_index=False).agg(f)
min_days.columns = ['person_id','min_days_to_prev_year','min_days_to_next_year']
df_offset = pd.merge(df_ranges[['person_id','dates']], min_days, on='person_id',how='inner')
我想做的是
a) 根据 min_days_to_prev_year
或 min_days_to_next_year
cols 中的 rand 值创建一个名为 rand_number
col 的新列
b) rand_number
列的 rand 值基于以下 2 个条件
a) rand_value from `min_days_to_prev_year` - `range is 0 to -N` (ex: 0 to -363 for person 11)
b) rand_value from `min_days_to_next_year` - `range is 0 to +N` (ex: 0 to +1 for person 11)
It's possible that both columns have `0` as value, then we just take 0.
c) 想要提一下,列的选择应该是随机的(例如:一些随机受试者应该具有基于 min_days_to_prev_year
的 rand_value,而另一些则基于 min_days_to_next_year
)
我正在尝试类似下面的事情
df_offset['rand_number'] = np.random.randint(df_offset['min_days_to_prev_year'].astype(int),df_offset['min_days_to_next_year'].astype(int), df_offset.shape[0])
我希望我的输出如下所示
最佳答案
我会在[0,1]
上生成随机数并相应地缩放:
np.random.seed(10)
rand = np.random.random(len(df_offset))
df_offset['rand_number'] = (rand * (df_offset.min_days_to_next_year + df_offset.min_days_to_prev_year)
- df_offset.min_days_to_prev_year
).astype(int)
输出:
person_id dates min_days_to_prev_year min_days_to_next_year rand_number
-- ----------- ------------------- ----------------------- ----------------------- -------------
0 11 1961-12-30 00:00:00 363 1 -82
1 12 1967-05-29 00:00:00 148 216 -140
2 13 1957-01-01 00:00:00 0 364 230
3 14 1959-07-27 00:00:00 207 157 65
关于python - 根据随机选择的列生成随机天数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62535573/