我有以下 JSON 数据:
% cat test2
{"day":"2020-07-15","map":
{"a":"ask","b":"bid","t":"timestamp"},"msLatency":52,"pair":"EUR/USD","status":"success","ticks":[
{"b":1.14105,"a":1.14106,"x":48,"t":1594771200000},
{"b":1.14105,"a":1.14106,"x":48,"t":1594771201000},
{"b":1.14103,"a":1.14104,"x":48,"t":1594771202000},
{"b":1.141,"a":1.1413,"x":48,"t":1594771203000},
{"b":1.14103,"a":1.14104,"x":48,"t":1594771205000},
{"b":1.14094,"a":1.14095,"x":48,"t":1594778803000}],"type":"forex"}
我想要得到:
1.14105,1.14106,1594771200000
1.14105,1.14106,1594771201000
1.14103,1.14104,1594771202000
1.141,1.1413,1594771203000
1.14103,1.14104,1594771205000
1.14094,1.14095,1594778803000
理想情况下,输出还应该用零填充,其中 1 和 5 是参数,用于指定前两列是具有 1 个自然位和 5 个小数位的数字(尽管可以使用 awk
轻松完成此步骤):
1.14105,1.14106,1594771200000
1.14105,1.14106,1594771201000
1.14103,1.14104,1594771202000
1.14100,1.14130,1594771203000
1.14103,1.14104,1594771205000
1.14094,1.14095,1594778803000
我已经用 JQ 尝试过:
% cat test2 | jq '.ticks'
[
{
"b": 1.14105,
"a": 1.14106,
"x": 48,
"t": 1594771200000
},
{
"b": 1.14105,
"a": 1.14106,
"x": 48,
"t": 1594771201000
},
{
"b": 1.14103,
"a": 1.14104,
"x": 48,
"t": 1594771202000
},
{
"b": 1.141,
"a": 1.1413,
"x": 48,
"t": 1594771203000
},
{
"b": 1.14103,
"a": 1.14104,
"x": 48,
"t": 1594771205000
},
{
"b": 1.14094,
"a": 1.14095,
"x": 48,
"t": 1594778803000
}
]
但我不知道如何将其转换为 CSV。
编辑: 作为引用,我之前有过以下解析,这里使用 JQ 是更简单的选择:
cat test2 |
sed -e 's/{\"/#{\"/g' |
tr '#' '\n' |
grep -v "timestamp" |
grep -v "day" |
sed '/^[[:space:]]*$/d' |
sed 's/].*$//g' |
sed 's/{//g' |
sed 's/},//g' |
sed 's/}//g' |
sed 's/\"//g' |
awk -F '[:,]' -v decimal_places=5 -v integer_places=1 '{
for(i=1; i<=NF; i=i+2) {
value[$i]=$(i+1);
};
format_price="%0" integer_places "." decimal_places "f"
format=format_price " " format_price " %d\n"
printf(format,value["b"],value["a"],value["t"]);
}'
最佳答案
解决方案如下:
jq -r '.ticks[] | [.b, .a, .t] | join(",")' test2
1.14105,1.14106,1594771200000
1.14105,1.14106,1594771201000
1.14103,1.14104,1594771202000
1.141,1.1413,1594771203000
1.14103,1.14104,1594771205000
1.14094,1.14095,1594778803000
它不会填充 5 位数字。我不知道如何在 jq 中做到这一点。我仍然认为另一种语言会更容易。
关于json - 如何使用 JQ 在命令行中将 JSON 列表提取到 CSV 中?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62938833/