javascript - 正则表达式获取 () 之间的字符串

Question

我有文字

   var text =  (hello) world this is (hi) text

我想编写一个正则表达式函数，这样我就可以得到

parseText(text) // returns ['hello', 'hi']

我尝试过这个但不起作用:

'(hello) world this is (hi) text'.match('((.*?))')

感谢您的帮助

Answer 1

你可以尝试: /\([^\)]+\)/g

1. \(:转义字符
2. [^\)]+:一个或多个字符^{(包括符号)}直到)个字符。
3. \):转义字符
4. g 标志:搜索所有巧合

const regex = /\([^\)]+\)/g;
const str = `(hello) world this is (hi) text`;

console.log(
  str.match(regex) // this returns an string array
    .map(i => i.slice(1, -1)) // remove first and last char
);

提示:

About point #2, you can change to [\)]* to take effect over zero or more character.

If you need only string, you can use \w+ or \w*.

If you need only words you can use /\(\b\w+\b\)/g