ruby-on-rails - 将调用记录解析为哈希数组 - Ruby

Question

我正在解析通话记录。转录内容以字符串形式返回，格式如下:

"Operator: Hi, please welcome Bob Smith to the call. Bob Smith: Hello there, thank you for inviting me...Now I will turn the call over to Stacy. Stacy White: Thanks Bob. As he was saying...."

每个新发言者开始发言时不会有新的台词。

我想将上面的字符串转换为哈希数组。类似于以下内容:

[ { speaker: "Operator",
    content: "Hi, please welcome Bob Smith to the call" },
  { speaker: "Bob Smith",
    content: "Hello there, thank you for inviting me...Now I will turn the call over to Stacy." }, 
  { speaker: "Stacy White",
    content: "Thanks Bob. As he was saying...." }
]

我想我需要使用某种正则表达式来解析它，但即使花了一上午的时间阅读它，也不知道如何解析它。如有任何帮助，我们将不胜感激。

谢谢

更新:

对于可能觉得这有用的其他人，这是我最终使用下面建议的解决方案得出的结果:

def display_transcript
  transcript_pretty = []
  transcript = self.content
  transcript_split = transcript.split(/\W*([A-Z]\w*\W*\w+):\W*/)[1..-1]
  transcript_split_2d = transcript_split.each_slice(2).to_a
  transcript_split_2d.each do |row|
    blurb = { speaker: row[0], content: row[1]}
    transcript_pretty << blurb
  end

  return transcript_pretty
end

Answer 1

我可以给你一个可以用来分解字符串的表达式。 从那里你可以自己承担责任，我相信你不会希望我夺走你实现目标的乐趣吧？ :>)

string = "Operator: Hi, please welcome Bob Smith to the call. Bob Smith: Hello there, thank you for inviting me...Now I will turn the call over to Stacy. Stacy White: Thanks Bob. As he was saying...."
split_up = string.split(/\W*(\w*\W*\w+):\W*/)[1..-1]
Hash[*split_up]
# {"Operator"=>"Hi, please welcome Bob Smith to the call", "Bob Smith"=>"Hello there, thank you for inviting me...Now I will turn the call over to Stacy", "Stacy White"=>"Thanks Bob. As he was saying...."}

一些解释:正则表达式查找一两个单词(\w*\W*\w+)，最后在前面加上一个点和一个空格\W* 后面是一个双点，最后是空格，后面是 :\W* 该表达式用于分割数组中的字符串。 结果始终以空字符串开头，因此您可以通过 [1..-1] 删除它 接下来，将该数组转换为哈希，第一个元素是键，第二个元素是值，依此类推，直到数组末尾。