我有表格和行
CREATE TABLE `TEST_TRANSACTIONS`.`Users` (
`id` INT NOT NULL AUTO_INCREMENT,
`balance` INT NOT NULL,
`payed` INT NOT NULL,
`isSimpleUser` INT NOT NULL,
`approvedAdminId` VARCHAR(45) DEFAULT NULL,
PRIMARY KEY (`id`));
INSERT INTO `TEST_TRANSACTIONS`.`Users` (`id`, `balance`, `payed`, `isSimpleUser`) VALUES ('1', '1', '2', '0');
INSERT INTO `TEST_TRANSACTIONS`.`Users` (`id`, `balance`, `payed`, `isSimpleUser`) VALUES ('2', '2', '4', '0');
INSERT INTO `TEST_TRANSACTIONS`.`Users` (`id`, `balance`, `payed`, `isSimpleUser`, `approvedAdminId`) VALUES ('3', '10', '20', '1', '53ed3434asd');
INSERT INTO `TEST_TRANSACTIONS`.`Users` (`id`, `balance`, `payed`, `isSimpleUser`, `approvedAdminId`) VALUES ('4', '25', '35', '1', '35sdd2342ss');
INSERT INTO `TEST_TRANSACTIONS`.`Users` (`id`, `balance`, `payed`, `isSimpleUser`) VALUES ('5', '4444', '5555', '1');
我想要余额总和，并为具有approvedAdminId的简单用户(isSimpleUser = 1并且approvedAdminId不为NULL)和非简单用户(isSimpleUser = 0)付款>
预期结果
sumBalancePremiumUsers sumPayedPremiumUsers sumBalanceSimpleApprovedUsers sumPayedSimpleApprovedUsers
3 6 35 55
最佳答案
SELECT
SUM(IF(isSimpleUser = 0, balance, 0)) AS sumBalancePremiumUsers,
SUM(IF(isSimpleUser = 0, payed, 0)) AS sumPayedPremiumUsers,
SUM(IF(isSimpleUser AND approvedAdminId IS NOT NULL, balance, 0)) AS sumBalanceSimpleApprovedUsers,
SUM(IF(isSimpleUser AND approvedAdminId IS NOT NULL, payed, 0)) AS sumPayedSimpleApprovedUsers
FROM Users
输出:
+------------------------+----------------------+-------------------------------+-----------------------------+
| sumBalancePremiumUsers | sumPayedPremiumUsers | sumBalanceSimpleApprovedUsers | sumPayedSimpleApprovedUsers |
+------------------------+----------------------+-------------------------------+-----------------------------+
| 3 | 6 | 35 | 55 |
+------------------------+----------------------+-------------------------------+-----------------------------+
关于jquery - 子查询双穿+聚合函数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/70296388/