我有一个表,其中包含集合类型。我想从表中SELECT
和GROUP BY
某些列。我希望每个组的结果都包含一个集合,该集合包含该组中所有单独集合的不同并集。
例如,
CREATE OR REPLACE TYPE my_varchar2_list AS TABLE OF VARCHAR2 (80);
WITH test_data (id, a_list) AS
(SELECT 1,
NEW my_varchar2_list ('A', 'B', 'C')
FROM DUAL
UNION ALL
SELECT 1,
NEW my_varchar2_list ('C', 'D', 'E')
FROM DUAL)
SELECT id,
... some magic syntax here...
FROM test_data
GROUP BY id
Desired results:
1, ('A','B','C','D','E')
我在寻找答案
我只是在寻找可以插入上面的“魔法语法在这里”占位符的表达式。我知道我可以通过将 TABLE(a_list)
连接到主表或以其他方式重组我的查询(或者,当然,使用 PL/SQL)来完成聚合。但是,我现在想避免使用此类解决方案。
最佳答案
改编自my answer另一个问题。
Oracle 设置:
CREATE OR REPLACE TYPE VARCHAR2s_Table IS TABLE OF VARCHAR2(100);
/
创建用户定义的聚合类型:
CREATE OR REPLACE TYPE Varchar2sTableUnion AS OBJECT(
list VARCHAR2s_Table,
STATIC FUNCTION ODCIAggregateInitialize(
ctx IN OUT Varchar2sTableUnion
) RETURN NUMBER,
MEMBER FUNCTION ODCIAggregateIterate(
self IN OUT Varchar2sTableUnion,
value IN VARCHAR2s_Table
) RETURN NUMBER,
MEMBER FUNCTION ODCIAggregateTerminate(
self IN OUT Varchar2sTableUnion,
returnValue OUT VARCHAR2s_Table,
flags IN NUMBER
) RETURN NUMBER,
MEMBER FUNCTION ODCIAggregateMerge(
self IN OUT Varchar2sTableUnion,
ctx IN OUT Varchar2sTableUnion
) RETURN NUMBER
);
/
CREATE OR REPLACE TYPE BODY Varchar2sTableUnion
IS
STATIC FUNCTION ODCIAggregateInitialize(
ctx IN OUT Varchar2sTableUnion
) RETURN NUMBER
IS
BEGIN
ctx := Varchar2sTableUnion( NULL );
RETURN ODCIConst.SUCCESS;
END;
MEMBER FUNCTION ODCIAggregateIterate(
self IN OUT Varchar2sTableUnion,
value IN VARCHAR2s_Table
) RETURN NUMBER
IS
BEGIN
IF value IS NULL THEN
NULL;
ELSIF self.list IS NULL THEN
self.list := value;
ELSE
self.list := self.list MULTISET UNION DISTINCT value;
END IF;
RETURN ODCIConst.SUCCESS;
END;
MEMBER FUNCTION ODCIAggregateTerminate(
self IN OUT Varchar2sTableUnion,
returnValue OUT VARCHAR2s_Table,
flags IN NUMBER
) RETURN NUMBER
IS
BEGIN
returnValue := self.list;
RETURN ODCIConst.SUCCESS;
END;
MEMBER FUNCTION ODCIAggregateMerge(
self IN OUT Varchar2sTableUnion,
ctx IN OUT Varchar2sTableUnion
) RETURN NUMBER
IS
BEGIN
IF self.list IS NULL THEN
self.list := ctx.list;
ELSIF ctx.list IS NULL THEN
NULL;
ELSE
self.list := self.list MULTISET UNION DISTINCT ctx.list;
END IF;
RETURN ODCIConst.SUCCESS;
END;
END;
/
创建用户定义的聚合函数:
CREATE FUNCTION MULTISET_UNION( list VARCHAR2s_Table )
RETURN VARCHAR2s_Table
PARALLEL_ENABLE AGGREGATE USING Varchar2sTableUnion;
/
查询:
然后您可以使用它来执行查询中的聚合:
WITH test_data (id, a_list) AS
(SELECT 1,
varchar2s_table ('A', 'B', 'C')
FROM DUAL
UNION ALL
SELECT 1,
varchar2s_table ('C', 'D', 'E')
FROM DUAL)
SELECT id,
MULTISET_UNION( a_list )
FROM test_data
GROUP BY id
输出:
ID MULTISET_UNION(A_LIST)
-- -------------------------------------------
1 SCHEMA.VARCHAR2S_TABLE('A','B','C','D','E')
关于sql - 在 SQL GROUP BY 中聚合集合中的不同值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43643078/