在这样的定义中
typedef struct
{
myType array[N];
} myStruct;
myStruct obj;
我总是可以假设([edit] 假设会发生正确的转换，这不是这里问题的重点 [/edit])
(&obj == &obj.array[0])
将返回 TRUE，或者我是否应该担心编译器引入额外的填充以适应 myType 对齐要求？理论上这不应该发生，因为该结构只有一个字段，但我对此并不完全确定。
最佳答案
通过适当的转换，这将始终返回 true。
来自 C standard 的第 6.7.2.1 节:
13. Within a structure object, the non-bit-field members and the units in which bit-fields reside have addresses that increase in the order in which they are declared. A pointer to a structure object, suitably converted, points to its initial member (or if that member is a bit-field, then to the unit in which it resides), and vice versa. There may be unnamed padding within a structure object, but not at its beginning.
关于c++ - 在新结构中声明的数组的地址，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/37005295/